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fgiga [73]
2 years ago
5

A sound wave has a wavelength of 1.32 m and travels at a speed of

Physics
1 answer:
kati45 [8]2 years ago
6 0

Answer:

0.00377143

Explanation:

You would have to divide to get the frequency.


1.32/350 = 0.00377143

I apologize if it is incorrect-

I hope it helps! Have a great day!

Anygays-

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How high a hill can a car coast up (engine disengaged) if work done by friction is negligible and
aev [14]

Answer:

h= 46.66 m

Explanation:

Given that

Initial speed of the car ,u = 110 km/h

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lets height gain by car is h.

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v²=u²- 2 g h

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0²=30.55²- 2 x 10 x h           ( g = 10 m/s²)

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4 0
3 years ago
G (where g=9.8 m/s2). If an object’s mass is m=10. kg, what is its weight?
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A proton is confined to a space 1 fm wide (about the size of an atomic nucleus). What's the minimum uncertainty in its velocity?
Daniel [21]

Answer:

Minimum uncertainty in velocity of a proton,\Delta v\ge 3.15\times 10^7\ m/s      

Explanation:

It is given that,

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We need to find the minimum uncertainty in its velocity. We know that the Heisenberg Uncertainty principle gives the uncertainty between position and the momentum such that,

\Delta p.\Delta x\ge \dfrac{h}{4\pi}

Since, p = mv

\Delta (mv).\Delta x\ge \dfrac{h}{4\pi}

m \Delta v.\Delta x\ge \dfrac{h}{4\pi}

\Delta v\ge \dfrac{h}{4\pi m\Delta x}

\Delta v\ge \dfrac{6.63\times 10^{-34}}{4\pi \times 1.67\times 10^{-27}\times 10^{-15}}

\Delta v\ge 3.15\times 10^7\ m/s

So, the minimum uncertainty in its velocity is greater than 3.15\times 10^7\ m/s. Hence, this is the required solution.

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4 0
3 years ago
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