Answer:
a = 40 [m/s²]
Explanation:
These kinds of problems can be solved using Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F = m*a
where:
F = force = 6 [N]
m = mass = 0.15 [kg]
a = acceleration [m/s²]
![a=F/m\\a=6/0.15\\a=40[m/s^{2} ]](https://tex.z-dn.net/?f=a%3DF%2Fm%5C%5Ca%3D6%2F0.15%5C%5Ca%3D40%5Bm%2Fs%5E%7B2%7D%20%5D)
Answer:
584.32m
Explanation:
Firstly, we need to find the x and y components of each vector.
x-component for vector L=303cos205°=-274.61
y-component for vector L=303sin205°=-128.05
x-component for vector M=555cos105°=-143.64
y-component for vector M=555sin105°=536.09
Since it's the vector sum, we add the x and y components of each vector.
Resultant vector x-component -274.61+(-143.64)=-418.25
Resultant vector y-component -128.05+536.09=408.04
Now, to find the magnitude, we use the formula 
sqrt(-418.25^2+408.04^2)=584.32m
Check my work for errors just in case.
Answer:
The force on a bullet that results from summing all of the forces on that bullet is known as the net force on the bullet.
Explanation:
Net force represents the overall force or the total force acting on an object.
Here, the object is bullet and the net force acting on it is the addition of all the forces acting on the bullet.