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3 years ago

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Consider the train car described in the previous part. Another experiment is conducted in it: A net force of 20N is applied to a

n object of mass 5kg. Can you determine the acceleration of the object with respect to the train, and, if so, what is its value?

1 answer:

nordsb [41]3 years ago

7 0

Answer:

No

Explanation:

The supplied information about the object and train is incomplete. Acceleration is the rate at which the velocity of a body changes with time. Here the velocity and time is not given

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Sodium chloride (NaCl) is an ionic solid. It dissolves easily in water. Which property of water allows it to dissolve NaCl? Wate

Afina-wow [57]

Answer:

Water is a polar molecule.

Explanation:

The fundamental rule of solubility is that "like solutes would dissolve in like solvents". Both NaCl and water are polar compounds.

NaCl is an ionic compound which forms from transfer of an electron from the Cl atom and a loss of electron from Na. This leaves a separation of charge on both atoms with Na being positively charged and Cl being negatively charged. This charge separation makes NaCl a polar compound.

Water on the other hand is a polar covalent solvent. The covalent bond results from the sharing of electrons between oxygen and hydrogen atoms. Due to the more electronegative nature of Oxygen, it pulls the shared electron more closely to itself than the Hydrogen atom. This unequal sharing of the electron leaves a net positive charge on Hydrogen and a negative charge on Oxygen.

For this reason, NaCl will dissolve in water.

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3 years ago

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3 years ago

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No person who thinks scientifically places any faith in the predictions of astrologers. Nevertheless there are many people who r

Lilit [14]

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3 years ago

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Two identical carts are free to move along a straight frictionless track. At time t1, cart X is moving at 2.0 m/s when it collid

jarptica [38.1K]

Answer:

Explanation:

Using the law of conservation of momentum;

$m_1 u_1+m_2u_2 = m_1v_1+m_2v_2$

here;

There is a need for conservation of the total momentum that occurred before and after the collision.

So;

$m_1$ = mass of cart X

$m_2$ = mas 9f cart Y

$u_1$ = velocity of cart X (before collision)

$u_2$ = velocity of cart Y (before collision)

$v_1$ = velocity of cart X (after collision)

$v_2$ = velocity of cart Y (after collision)

So;

$m(u_1+0) =(m_1v+m_2)v$

because the mass is identical and v represents the velocity of both carts.

Now;

$u_1$ = 2 m/s

$u_2$ = 0 ( at rest)

∴

m(2) = (2m)v

v = 1 m/s

Thus, we can see from the graphical image attached below that the velocity of X reduces to 1 m/s after collision with cart Y.

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3 years ago

A hard-boiled egg of mass 46.0 gg moves on the end of a spring with force constant 25.6 N/mN/m . The egg is released from rest a

soldi70 [24.7K]

Answer:

0.022kg/s

Explanation:

We are given that

Mass of boiled egg=46 g= $\frac{46}{1000} kg=0.046 kg$

$1kg=1000 g$

Constant force=F=25.6 N/m

Initial displacement= $A_1=0.296 m$

Final displacement= $A_2=0.12 m$

Time=t=4.55 s

Damping force= $F_x=-bv_x$

We have to find the magnitude of damping constant b.

We know that the displacement of the oscillator under damping motion is given by

$x=Ae^{-\frac{b}{2m}t}cos(w't+\phi)$

For maximum displacement $cos(w't+\phi)=1$

Therefore , $x=A_2$

Substitute the values

$A_2=A_1e^{-\frac{-b}{2m}t}$

$e^{-\frac{b}{2m}t}=\frac{A_2}{A_1}$

$-\frac{b}{2m}t=ln\frac{A_2}{A_1}$

$lnx=y\implies x=e^y$

Substitute the values

$-\frac{b}{2\times 0.046}\times 4.55=ln\frac{0.12}{0.296}$

$\frac{2\times 0.046}{4.55b}=ln\frac{0.296}{0.12}$

$\frac{2\times 0.046}{4.55}=0.9b$

$b=\frac{2\times 0.46}{4.55\times 0.9}=0.022kg/s$

Hence,the magnitude of damping constant b=0.022kg/s

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2 years ago