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Andrej [43]
3 years ago
15

Consider the train car described in the previous part. Another experiment is conducted in it: A net force of 20N is applied to a

n object of mass 5kg. Can you determine the acceleration of the object with respect to the train, and, if so, what is its value?
Physics
1 answer:
nordsb [41]3 years ago
7 0

Answer:

No

Explanation:

The supplied information about the object and train is incomplete. Acceleration is the rate at which the velocity of a body changes with time. Here the velocity and time is not given

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HELP ASAP HELP Two tennis balls of the same mass are served at different speeds: 30 m/s and 60 m/s. Which serve has more kinetic
inna [77]

Answer:

<em>The second ball has four times as much kinetic energy as the first ball.</em>

Explanation:

<u>Kinetic Energy </u>

Is the type of energy an object has due to its state of motion. It's proportional to the square of the speed.

The equation for the kinetic energy is:

\displaystyle K=\frac{1}{2}mv^2

Where:

m = mass of the object

v = speed at which the object moves

The kinetic energy is expressed in Joules (J)

Two tennis balls have the same mass m and are served at speeds v1=30 m/s and v2=60 m/s.

The kinetic energy of the first ball is:

\displaystyle K_1=\frac{1}{2}m\cdot 30^2

\displaystyle K_1=\frac{1}{2}m\cdot 900

K_1=450m

The kinetic energy of the second ball is:

\displaystyle K_2=\frac{1}{2}m\cdot 60^2

\displaystyle K_2=\frac{1}{2}m\cdot 3600

K_2=1800m

Being m the same for both balls, the second ball has more kinetic energy than the first ball.

To find out how much, we find the ratio:

\displaystyle \frac{K_2}{K_1}=\frac{1800m}{450m}

Simplifying:

\displaystyle \frac{K_2}{K_1}=4

The second ball has four times as much kinetic energy as the first ball.

5 0
3 years ago
Read 2 more answers
Basketball player Darrell Griffith is on record as
Gre4nikov [31]

Explanation:

1.

We use the equation

h = \frac{gt^2}{2}, where

h is the height traveled,

g is the acceleration due to gravity and

t is the time taken to reach height h.

We can now calculate t to be

\sqrt{\frac{2*1.2 m}{9.81 m/s^2} }

= 0.495 s

Let v be the initial velocity of the player.

The player deaccelarates from v m/s to 0 m/s in 0.495 s at the rate of 9.81 m/s^2.

v = 9.81 m/s^2 x 0.495 s = 4.85 m/s

2.

The player takes 0.3 s to increase his velocity from 0 m/s to 4.85 m/s. So his average accelaration is

4.85 m/s / 0.3 s = 16.2 m/s^2

5 0
3 years ago
How are some types of collisions different from others?
lyudmila [28]
There are two general types of collisions, inelastic and elastic. 
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Collisions in which the objects do not touch each other are elastic. (Ex: Rutherford Scattering) 
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3 years ago
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