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Mama L [17]
3 years ago
9

Order these numbers in least to greatest (THIS IS NOT A TEST OR ASSIGNMENT) I do need help ASAP and I WILL GIVE BRAINLIEST

Mathematics
2 answers:
Pie3 years ago
7 0

Answer:

1. LESS THAN ( 6.4... < 6.8)

2. GREATER THAN ( -6.4... > -6.8)

3. GREATER THAN (1.44 > -1.44)

4. LESS THAN (-3.1... < -3)

Step-by-step explanation:

Misha Larkins [42]3 years ago
5 0

Answer:

1. <

2. >

3. >

4.<

least to greatest:

-6.8< -\sqrt{41}< -\sqrt{10}< -3< -(1.2)^{2}< (-1.2)^{2}< \sqrt{41}< 6.8

Step-by-step explanation:

1. 6.4 and 6.8

2.  -6.4 and -6.8

3. 1.44 and -1.44

4. -3.16 and -3

the third one on the picture is wrong

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Write the equation of the line with an x-intercept at (0,2) and perpendicular to 3x+4y=12.
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First you normalize 3x+4y=12 into y = -3/4 x + 3 (dividing by 4).

Then you observe that the slope of the line is -3/4 (it's always the factor with the x). A perpendicular line has the reciprocal slope. Reciprocal means inverted and negated. So -3/4 becomes +4/3.

The equation will thus look like y = 4/3 x + b. To find b, we fill in the given x intercept (0,2), (we get 2 = 4/3 * 0 + b). With x=0, b must be 2.

So the equation is: y = 4/3 x + 2

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Melissa drove 715 miles in 11 hours.
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Answer:

455 miles driven in 7hrs

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17:65<br> tell whether the ratio is in simplest form
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Identify the scale factor for the dilation below if ABCD is the preimage.
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I NEED HELP !!! 30 points!!!! and brainliest :)<br><br>please give sensible answer :(<br><br><br>​
Allushta [10]

Answer:

Step-by-step explanation:

9) PQR Is an isosceles triangle

=> ∠PRQ = (180° - x)/2

PRS is an isosceles right triangle

=> ∠PRS = 45°

Have: ∠PRS + ∠PRQ = 115°

=> \frac{180-x}{2}+45=115 \\

=> 180 - x = (115 - 45).2 = 140

<=> x = 180 - 140 = 40

10) ABD is an isosceles right triangle => ∠ABD = 45°

BCD is an equilateral triangle => ∠CBD = 60°

have: x = ∠ABD + ∠CBD = 45° + 60° = 105°

11) have: x = y (2)

PQT is an isosceles triangle => ∠PQT = 180 - 70.2 = 40

QTS   is an isosceles triangle => ∠TQS = 180 -2x

QRS   is an isosceles triangle => ∠RSQ = y

have: 40 + 180 - 2x + y = 180 => 2x - y = 40 (1)

(1)(2) => \left \{ {{y=x} \atop {2x-y=40}} \right.\\\\=> \left \{ {{x=40} \atop {y=40}} \right.

=> x + y = 80

12) EFJ Is an equilateral  triangle => ∠FJE = 60

∠FJE is the outer angle of the triangle FHJ but FHJ is an isosceles triangle

=> 60 = 2.∠JHF => ∠JHF = 30°

∠JHF is the outer angle of the triangle FHG

=> 30° = 2x

<=> x = 15°

7 0
3 years ago
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