Let
cos x=7/18
x=arc cos (7/18)-----> using a calculator-------> x=67.11°-----> x=1.17 radians
the answer is
x=67.11° or x=1.17 radians
DEF= 6 ft^2
A= 1/2*b*h
Plug in what you know.
6= 1/2*4*h
Multiply like terms.
6=2*h
Divide 2 on both sides.
3=h
If the base of ABC= 12
12/4=3
3*3=9
A= 1/2*b*h
A= 1/2*12*9
A= 1/2*84
A= 42
The area of ABC is 42 ft^2
I hope this helps!
~kaikers
I believe it’s the second option, f=14 g=14 with the square root of 3
Answer:
4 or monke
Step-by-step explanation:
