So, the force of gravity that the asteroid and the planet have on each other approximately 
<h3>Introduction</h3>
Hi ! Now, I will help to discuss about the gravitational force between two objects. The force of gravity is not affected by the radius of an object, but radius between two object. Moreover, if the object is a planet, the radius of the planet is only to calculate the "gravitational acceleration" on the planet itself,does not determine the gravitational force between the two planets. For the gravitational force between two objects, it can be calculated using the following formula :

With the following condition :
- F = gravitational force (N)
- G = gravity constant ≈
N.m²/kg²
= mass of the first object (kg)
= mass of the second object (kg)- r = distance between two objects (m)
<h3>Problem Solving</h3>
We know that :
- G = gravity constant ≈
N.m²/kg²
= mass of the planet X =
kg.
= mass of the planet Y =
kg.- r = distance between two objects =
m.
What was asked :
- F = gravitational force = ... N
Step by step :





<h3>Conclusion</h3>
So, the force of gravity that the asteroid and the planet have on each other approximately

<h3>See More</h3>
R=ut+gt^2/2
r- displacement (height to find)
u - initial speed (zero)
t - time taken
r=0*5.8 + 10*5.8^2 /2 = 168.2 meters
We can’t see the following
1. Frequency: 
The frequency of a light wave is given by:

where
is the speed of light
is the wavelength of the wave
In this problem, we have light with wavelength

Substituting into the equation, we find the frequency:

2. Period: 
The period of a wave is equal to the reciprocal of the frequency:

The frequency of this light wave is
(found in the previous exercise), so the period is:

Answer:

Explanation:
The Coulomb's law states that the magnitude of the electrostatic force between two charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them:

In this case, we have
:
