A 3.00-kg ball swings rapidly in a complete vertical circle of radius 2.00 m by a light string that is fixed at one end. The bal
1 answer:
Answer
given,
mass of the ball = 3 kg
swing in vertical circle with radius = 2 m
work done by the gravity = ?
work done by the tension = ?
Work done by the gravity = - m g Δh
Δ h = 2 + 2 = 4 m
Work done by the gravity =
= -117.6 J
work done by gravity is equal to -117.6 J
Work done by tension will be equal to zero.
Zero because tension is always perpendicular to velocity
work done by tension is equal to 0 J
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The gravitational field gx at the surface of planet x (M/m)(r/R)² times the gravitational field gy at the surface of planet y.
<h3>What is gravitational field?</h3>A gravitational field, as defined by physics, is the influence a massive body has on the area surrounding it, exerting a force on another huge body. In other words, a gravitational field, which is measured in newtons per kilograms (N/kg), aids in the explanation of gravitational field.
Now, Let planet x has mass M and radius R: then gravitational field at the surface of planet: gₓ = GM/R².
Let planet y has mass m and radius r: then gravitational field at the surface of planet: = Gm/r².
Hence, gₓ/ = (M/m)(r/R)².
So, the gravitational field gx at the surface of planet x (M/m)(r/R)² times the gravitational field gy at the surface of planet y.
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