A 3.00-kg ball swings rapidly in a complete vertical circle of radius 2.00 m by a light string that is fixed at one end. The bal
1 answer:
Answer
given,
mass of the ball = 3 kg
swing in vertical circle with radius = 2 m
work done by the gravity = ?
work done by the tension = ?
Work done by the gravity = - m g Δh
Δ h = 2 + 2 = 4 m
Work done by the gravity =
= -117.6 J
work done by gravity is equal to -117.6 J
Work done by tension will be equal to zero.
Zero because tension is always perpendicular to velocity
work done by tension is equal to 0 J
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Answer:
False.
Explanation:
From Kepler's Third Law of plenetary motion, we know that:
<em>"The square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit."</em>
Or, as expressed in mathematical terms:
, where <em>a</em> is the semi-major axis of the orbit (the distance from the center), and <em>T </em>is the orbital period of the satellite.
From this expression we can clearly see that if the orbit's semi-major axis is doubled, orbital period will be times longer to compensate the variation.