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galina1969 [7]
3 years ago
11

Describe how different types of motion are represented by distance-time graphs and velocity-time graphs.

Physics
1 answer:
eduard3 years ago
4 0

Answer:

non-accelerated movement

velocity versus time  a horizontal straight line.

distance versus time  gives a horizontal straight line.

accelerated motion

graph of velocity versus time s an inclined line and the slope

graph of distance versus time is a parabola of the form

Explanation:

In kinematics there are two types of steely and non-accelerated movements

In a  the velocity of the body is constant therefore a speed hook against time gives a horizontal straight line.

A graph of distance versus time is a straight line whose slope is the velocity of the body

          x = v t

In an accelerated motion the velocity changes linearly with time, so a graph of velocity versus time is an inclined line and the slope is the value of the acceleration of the body

         v = v₀ + a t

A graph of distance versus time is a parabola of the form

         x =v₀ t + ½ a t²

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3 years ago
A scientific law is ____________________A. A rule enacted by the National Academy of Sciences. B. What scientists expect will al
lapo4ka [179]

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3 years ago
According to boyle’s law, the volume of a gas is inversely proportional to its pressure if the?
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Read 2 more answers
The load across a 12 V battery consists of a series combination of three resistors 34 Ω, 42Ω, and 30Ω. What is the total resista
stira [4]

Answer:

The total resistance is 106 Ω and the current in the circuit is 0.11 A.

Explanation:

Given that,

Voltage of the battery, V = 12 V

Resistors 34 Ω, 42Ω, and 30Ω are connected in series.

The total resistance is given by :}

R = 34 + 42 +30

= 106Ω

Let I is the total current in the circuit. Using ohm's law to find it such that,

I=\dfrac{V}{R}\\\\I=\dfrac{12}{106}\\\\I=0.11\ A

Hence, the total resistance is 106 Ω and the current in the circuit is 0.11 A.

4 0
3 years ago
Hi, I'm having a lot of trouble with this one. The answer I got to was 407.91 but I'm not confident in it.
Alecsey [184]

Answer:

6.20×10⁴ V/m

Explanation:

The magnitude of electric field is:

E = √(Eₓ² + Eᵧ²)

where Eₓ = ∂φ/∂x and Eᵧ = ∂φ/∂y.

φ = 1.11 (x² + y²)^-½ − 429x

Eₓ = -0.555 (x² + y²)^-(³/₂) (2x) − 429

Eᵧ = -0.555 (x² + y²)^-(³/₂) (2y)

Evaluating at (0.003, 0.003):

Eₓ = -44034 V/m

Eᵧ = -43605 V/m

The magnitude is:

E = 61971 V/m

Rounded to three significant figures, the strength of the electric field is 6.20×10⁴ V/m.

3 0
4 years ago
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