Answer:
Re=160ohm
Explanation:
Step#1
Rt=R1+R2 ( because both are in series)
Rt=(100+220 ) ohm
Rt=320 ohm
Step#2
Rt and R3 are parallel so,
Re= (Rt× R3) ÷ (Rt+R3)
Re= (320×320)÷( 320+320)
Re = 102,400÷ 640
Re=160ohm
Answer:
Voltage in primary coil is 3.91 V
Explanation:
For transformer we know that the working principle is given as
![\frac{V_1}{V_2} = \frac{N_1}{N_2}](https://tex.z-dn.net/?f=%5Cfrac%7BV_1%7D%7BV_2%7D%20%3D%20%5Cfrac%7BN_1%7D%7BN_2%7D)
here we know that
![V_1 [tex] = voltage in primary coil[tex]V_2 = 25 V](https://tex.z-dn.net/?f=V_1%20%5Btex%5D%20%3D%20voltage%20in%20primary%20coil%3C%2Fp%3E%3Cp%3E%5Btex%5DV_2%20%3D%2025%20V)
![N_1 = 500](https://tex.z-dn.net/?f=N_1%20%3D%20500)
![N_2 = 3200](https://tex.z-dn.net/?f=N_2%20%3D%203200)
Now we have
![\frac{V_1}{25} = \frac{500}{3200}](https://tex.z-dn.net/?f=%5Cfrac%7BV_1%7D%7B25%7D%20%3D%20%5Cfrac%7B500%7D%7B3200%7D)
![V_1 = 3.91 V](https://tex.z-dn.net/?f=V_1%20%3D%203.91%20V)
Answer:
They can be seen from a distance of 4.372 kilometers.
Explanation:
Using the Reyligh creterion for diffraction through a circular aperture we have
where symbol's have their usual meaning
thus applying values we get
![D=\frac{dx}{1.22\lambda }](https://tex.z-dn.net/?f=D%3D%5Cfrac%7Bdx%7D%7B1.22%5Clambda%20%7D)
![\therefore D=\frac{0.633\times 4.61\times 10^{-3}}{1.22\times 547\times 10^{-9}}\\\\D=4372.77m\\=4.372km](https://tex.z-dn.net/?f=%5Ctherefore%20D%3D%5Cfrac%7B0.633%5Ctimes%204.61%5Ctimes%2010%5E%7B-3%7D%7D%7B1.22%5Ctimes%20547%5Ctimes%2010%5E%7B-9%7D%7D%5C%5C%5C%5CD%3D4372.77m%5C%5C%3D4.372km)