Question

A consumer report counted 72 low quality, 112 medium quality, and 711 high quality computers based on a random sample. The report went on to say that all computers, regardless of quality, are packaged identically and sold at the same price. Use the observed frequencies to create a probability model for the quality of the next computer purchased

Answer 1

Total number of computers in sample = 72 + 112 + 711 = 895.
P(LQ) = 72/895 = 0.08
P(MQ) = 112/895 = 0.125
P(HQ) = 711/895 = 0.794

Answer 2

Answer:

$P(L) = 0.0804$

$P(M) = 0.1251$

$P(H) = 0.7945$

Step-by-step explanation:

A probability is the number of desired outcomes desired by the number of total outcomes.

I am going to say that we have these following events

L is the event that a computer is low quality.

There are 72+112+711 = 895 computers. Of those, 72 are low quality. So

$P(L) = \frac{72}{895} = 0.0804$

M is the event that a computer is medium quality.

Of the 895 computers, 112 of them are medium quality. So

$P(M) = \frac{112}{895} = 0.1251$

H is the event that a computer is medium quality.

Of the 895 computers, 711 of them are medium quality. So

$P(H) = \frac{711}{895} = 0.7945$