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What do astronomers expect will eventually happen to the Milky Way galaxy?

Nataly [62]

<span> The Andromeda Milkyway is a galactic collision predicted to occur in 4 billion years. I believe thats the answer</span>

5 0

3 years ago

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A 500-g lump of clay is dropped onto a 1-kg cart moving at 60 cm/s. The clay is moving downward at 30 cm/s just before l dith t

viktelen [127]

Answer:

The speed of the cart and clay after the collision is 50 cm/s .

Explanation:

Given :

Mass of lump , m = 500 g = 0.5 kg .

Velocity of lump , v = 30 cm/s .

Mass of cart , M = 1 kg .

Velocity of cart , V = 60 cm/s .

We know by conservation of momentum :

$mv+MV=(m+M)v'$

Here , $v'$ is the speed of the cart and clay after the collision .

Putting all value in above equation .

We get :

$0.5\times 30+1\times 60=(0.5+1)\times v'\\\\v'=\dfrac{15+60}{1.5}\\\\v'=50\ cm/s$

Hence , this is the required solution .

3 0

3 years ago

An alpha particle travels at a velocity of magnitude 520 m/s through a uniform magnetic field of magnitude 0.034 T. (An alpha pa

Keith_Richards [23]

Answer:

(a) Magnetic force $F=38.584\times 10^{-19}N$

(b) Acceleration $a=5.846\times 10^8m/sec^2$

(C) Speed will remain same

Explanation:

We have given velocity of alpha particle v = 520 m/sec

Magnetic field B = 0.034 T

Charge on alpha particle $q=3.2\times 10^{-19}C$

Mass of alpha particle $m=6.6\times 10^{-27}kg$

Angle between velocity and magnetic field 43°

(a) Force acting on the particle is equal to

$F=q(v\times B)=qvBsin\Theta$

$F=3.2\times 10^{-19}\times 320\times 0.034\times sin43^{\circ}$

$F=38.584\times 10^{-19}N$

(B) According to newton's law

F = ma. here m is mass and a is acceleration.

So acceleration

$a=\frac{F}{m}=\frac{38.584\times 10^{-19}}{6.6\times 10^{-27}}=5.846\times 10^8m/sec^2$

(c) As the magnetic force is always perpendicular to velocity so speed will remain same neither decreases nor increases.

4 0

3 years ago

Please please please please PLEASE help!!!

inna [77]

Answer:

Because the electricity flows through and creates static bonds around the metal case which creates a bond with other fields that protects it.

Explanation:

8 0

3 years ago

An green hoop with mass mh = 2.8 kg and radius rh = 0.17 m hangs from a string that goes over a blue solid disk pulley with mass

vladimir2022 [97]

The mass of the hoop is the only force which is computed by:F net = 2.8kg*9.81m/s^2 = 27.468 N
the slow masses that must be quicker are the pulley, ring, and the rolling sphere.
The mass correspondent of M the pulley is computed by torque τ = F*R = I*α = I*a/R F = M*a = I*a/R^2 --> M = I/R^2 = 21/2*m*R^2/R^2 = 1/2*m
The mass equal of the rolling sphere is computed by: the sphere revolves around the contact point with the table. So using the proposition of parallel axes, the moment of inertia of the sphere is I = 2/5*mR^2 for spin about the midpoint of mass + mR^2 for the distance of the axis of rotation from the center of mass of the sphere. I = 7/5*mR^2 M = 7/5*m
the acceleration is then a = F/m = 27.468/(2.8 + 1/2*2 + 7/5*4) = 27.468/9.4 = 2.922 m/s^2

6 0

3 years ago