The width used for the car spaces are taken as a multiples of the width of
the compact car spaces.
Correct response:
- The store owners are incorrect
<h3 /><h3>Methods used to obtain the above response</h3>
Let <em>x</em><em> </em>represent the width of the cars parked compact, and let a·x represent the width of cars parked in full size spaces.
We have;
Initial space occupied = 10·x + 12·(a·x) = x·(10 + 12·a)
New space design = 16·x + 9×(a·x) = x·(16 + 9·a)
When the dimensions of the initial and new arrangement are equal, we have;
10 + 12·a = 16 + 9·a
12·a - 9·a = 16 - 10 = 6
3·a = 6
a = 6 ÷ 3 = 2
a = 2
Whereby the factor <em>a</em> < 2, such that the width of the full size space is less than twice the width of the compact spaces, by testing, we have;
10 + 12·a < 16 + 9·a
Which gives;
x·(10 + 12·a) < x·(16 + 9·a)
Therefore;
The initial total car park space is less than the space required for 16
compact spaces and 9 full size spaces, therefore; the store owners are
incorrect.
Learn more about writing expressions here:
brainly.com/question/551090
Answer:

Step-by-step explanation:
Given

Required
Solve for x

Open all brackets




Collect like terms


Solve fraction


Multiply both sides by 6



I’m Not 100% Sure, But I Would Think 13.1% Is The Answer.
Answer:
should be 6cm
Step-by-step explanation:
if you are looking at a cube
Answer:
B 3x+2
Step-by-step explanation:
perimiter=2L+2W
P=2(L+W)
if x=width then
P=2(L+x)
P=8x+8
hmm
8x+8=2(L+x)
distribute
8x+8=2L+2x
minus 2x both sides
6x+8=2L
divide both sides by 2
3x+4=L
the length is 3x+4
B is answer