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denpristay [2]
3 years ago
11

Un topografo situado en un punto c localiza dos puntos a y b en los lados opuestos de un lago . Si el punto c esta situado a 5km

de a y 8 km de b y ademas el angulo formado en el punto c es de 36 grados . Calcular el ancho del lago

Mathematics
2 answers:
denis23 [38]3 years ago
6 0

Hi mods, I do have a link in this answer but it is a link to the spanish version of brainly since this user seems to speak spanish.

Por favor, traduzca su pregunta al inglés o encuentre la versión en español de Brainly (https://brainly.com.br/ o https://brainly.lat/.)

Estoy usando el traductor de google, lo siento por el mal español

ver diagrama adjunto abajo (el asombrosamente dibujado)

podemos formar un triangulo

Usa la ley de los cosenos del segundo apego.

Queremos encontrar el valor de c que representa el ancho del lago

En este problema, a=5, b=8, y C=36°

c^2=a^2+b^2-2abcos(C)

c=\sqrt{a^2+b^2-2abcos(C)}

c=\sqrt{5^2+8^2-2(5)(8)cos(36^o)}

c=\sqrt{25+64-80cos(36^o)}

c=\sqrt{89-80cos(36^o)}

c≈4.92734 km


el ancho del lago es de aproximadamente 4.93km


Mariana [72]3 years ago
5 0
Can you write this question in English please..?
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Given that area of a rectangle is 90 square inch

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As ratio of length to the width is 5 : 2

Lets assume length of rectangle = 5x inches and width of rectangle = 2x inches.

<em><u>The formula for area of rectangle is given as:</u></em>

\text { Area of rectangle }=\text { length of rectangle } \times \text { width of rectangle}

Substituting the given value of area of rectangle and assumed value of length and width of rectangle we get:

\begin{array}{l}{90=5 x \times 2 x} \\\\ {=>90=10 x^{2}}\end{array}

On solving the above expression for x we get

\begin{array}{l}{=>\frac{90}{10}=x^{2}} \\\\ {=>x^{2}=9} \\\\ {=>x=\sqrt{9}=3}\end{array}

\begin{array}{l}{\text { Length of rectangle }=5 \times x=5 \times 3=15 \text { inches }} \\\\ {\text { Width of rectangle }=2 \times} x=2 \times} 3=6 \text { inches }}\end{array}

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