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3 years ago

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Mathematics

2 answers:

valina [46]3 years ago

6 0

david's procedure is correct becsuse Keisha didnt put the correct value of sin theta in equation, she forgot to mention negative sign. though solution are same but in other case it could have gone wrong

taurus [48]3 years ago

6 0

Answer 1:

Option C - Both procedures are correct.

Step-by-step explanation:

As for Keisha's method of solving the question

Tan^2 Q + 1 = Sec^2Q
Sin^2 Q/ Cos^2 Q +1 = 1 / Cos^2 Q
(8/17)^2 / Cos^2 Q + 1 / Cos ^2 Q
Cos Q = +- Square root of 1 - 64/289
Cos Q = +- 15/17

Therefore, Keisha's procedure is correct

<h3>Answer 2: </h3>

Option C - Both procedures are correct.

Step-by-step explanation:

As for David's method of solving the question.

Sin^2 Q + Cos^2 Q = 1
Cos^2 Q = 1 - (-8/17)^2
Cos Q = +- Square Root of 225/289
Cos Q = +- 15/17

Therefore David's procedure is correct.

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timurjin [86]

Given system of inequalities: y > 2/5(x) - 2 and y < -3x + 1.

We are given greater than (>) inequality symbol in first inequality.

For "only greater than inequality symbol" we would draw only a "dotted line".

Also in second inequality we have less than (<) inequality symbol.

For "only greater than inequality symbol" we would draw only a "dotted line".

In the shared graph, both the lines plotted are solid lines.

Therefore, correct option is B) The lines graphed should be dashed.

7 0

4 years ago

Read 2 more answers

Kelly is going to shop with the $200.00 that she earned from doing chores. She wants to save 30% of her money to put into a savi

Evgesh-ka [11]

Answer:

No she won't

Step-by-step explanation:

200(0.30)=60

60(0.06)=3.6

60+3.6=63.6

75(0.06)=4.5

75+4.5=79.5

79.5+63.6=143.1

200-143.1=56.9

56.9<60

6 0

4 years ago

Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m

GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

$d=\sqrt{\frac{3h}{2} }$