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Alinara [238K]
3 years ago
11

Convert 19.2 moles to kL ??

Chemistry
1 answer:
noname [10]3 years ago
8 0

Answer:

30.8994048km

Explanation:

19.2 mi * 1.609344 km/1mi = 30.8994048 km

A common question isHow many mile in 19.2 kilometer?And the answer is 11.930326891 mi in 19.2 km. Likewise the question how many kilometer in 19.2 mile has the answer of 30.8994048 km in 19.2 mi.

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__________ solutions are very unstable.
Serhud [2]

Answer:

none of the above

Explanation:

because all of them are unstable

3 0
3 years ago
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which type of chemical reaction occurs faster at equilibrium the formation of production from reactants or that of reactants fro
Degger [83]

Answer :-

None of the forward reaction or backward reaction will be faster at equilibrium as

definition of equilibrium is that phase in which the rate of formation of product from reactant and rate formation of reactant from product is equal

and hence , both will be form at equal rate !!

3 0
3 years ago
List four physical properties of a glass of milk
aniked [119]
Its white
It has temperature
It has density and 
It has volume! :) 
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4 years ago
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Why Basalt and gabbro are denser than granite and<br> obsidian?
Maksim231197 [3]

Answer:

What do you think causes some rock types to have higher densities than others? (Assuming there are no air pockets in the rock, the types of minerals will determine the density. Granite contains lots of quartz and feldspar - both fairly light minerals, whereas basalt and gabbro are made of heavier minerals.)

Explanation:

4 0
3 years ago
1A. A strontium hydroxide solution is prepared by dissolving 10.45 g of Sr(OH)2 in water to make 41.00 mL of solution. What is t
horrorfan [7]

Answer:

1. 0.00352 M

2. 2HNO3(aq) + Sr(OH)2(aq) -----> Sr(NO3)2(aq) + 2H2O(l)

3. 0.00534 M

Explanation:

1.

Mass of strontium hydroxide= 10.45 g

Volume of solution = 41.00 ml

Number of moles = mass of Sr(OH)2/molar mass of Sr(OH)2 = 10.45g/121.63 g/mol= 0.0859 moles

Molarity= number of moles × volume = 0.0859 ×41/1000 = 0.00352 M

2.

2HNO3(aq) + Sr(OH)2(aq) -----> Sr(NO3)2(aq) + 2H2O(l)

3.

Concentration of acid CA= the unknown

Volume of acid VA= 31.5 ml

Concentration of base CB= 0.00352 M

Volume of base VB= 23.9 ml

Number of moles of acid NA= 2

Number of moles of base NB= 1

From;

CAVA/CBVB = NA/NB

CAVANB= CBVBNA

CA= CBVBNA/VANB

CA= 0.00352 × 23.9 ×2/31.5 ×1

CA= 0.00534 M

7 0
3 years ago
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