1) (Hvap)(moles of water)=236.9783574kJ
(40.67)(105/18.02)
2) (change in temperature)(mass)(Cliquid)=43.9345172kJ
(100)(105/18.02)(75.4)/1000
3) (Hfus)(moles of water)=35.01942286kJ
(6.01)(105/18.02)
4) (change in temperature)(mass)(Csolid)=3.181465039kJ
(15)(105/18.02)(36.4)/1000
Total released=319.1137625kJ
At constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 20.85L.
<h3>
What is
Avogadro's law?</h3>
Avogadro's law states that "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules."
It is expressed as;
V₁/n₁ = V₂/n₂
Given the data in the question;
- Initial amount of gas n₁ = 2moles
- Initial volume v₁ = 13.9L
- Final amount of gas n₁ = 3moles
V₁/n₁ = V₂/n₂
V₁n₂ = V₂n₁
V₂ = V₁n₂ / n₁
V₂ = (13.9L × 3moles) / 2moles
V₂ = 41.7molL / 2mol
V₂ = 20.85L
At constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 20.85L.
Learn more about Avogadro's law here: brainly.com/question/15613065
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Answer:
B. it accounts for all the energy in the good even if some of its largely excreted by th body
Answer:
w = -531 kJ
1. Work was done by the system.
Explanation:
Step 1: Given data
- Heat gained by the system (q): 687 kJ (By convention, when the system absorbs heat, q > 0).
- Change in the internal energy of the system (ΔU°): 156 kJ
Step 2: Calculate the work done (w)
We will use the following expression.
ΔU° = q + w
w = ΔU° - q
w = 156 kJ - 687 kJ
w = -531 kJ
By convention, when w < 0, work is done by the system on the surroundings.
Answer:
no, and next time take it right
Explanation:
