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3 years ago

10

Austin tried to remember his friend's house number. He knew that there were three digits: a 5, another 5 and a 7. He could not r

emember the order. How many different house numbers could it be?
a) 3
b) 6
c) 17
d) 27

2 answers:

vladimir1956 [14]3 years ago

8 0

Answer:

3

Step-by-step explanation:

557

575

755

Mashutka [201]3 years ago

5 0

Answer:

3

Step-by-step explanation:

557

575

755

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Your monthly living expenses are $1500 on an income of $1,650 per month. Your goal is to have an emergency fund of 4 times your

Aneli [31]

For the answer to the question above, your end goal is to have $6,000 total in 12 months. since you have $2400 already you can subtract that from 6,000 leaving you with $3600 over the course of 12 months. since you already put $150 in a month over the course of 12 months you would have $1800 which is only half of the goal of $3600. in order for you to put in $3600, you would have to put an additional 150 in your savings along with your regular 150 making Letter B the answer.

4 0

3 years ago

Read 2 more answers

What is the greatest common factor for 200,205

bixtya [17]

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6 0

3 years ago

The Copy Shop has made 20 copies of a document for you. Since the defective rate is 0.1, you think there may be some defective c

Pepsi [2]

Answer:

Binomial

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

Step-by-step explanation:

For each copy of the document, there are only two possible outcomes. Either it is defective, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem

Of the 20 copies, 2 are defective, so $p = \frac{2}{20} = 0.1$ .

What is the probability that you will encounter neither of the defective copies among the 10 you examine?

This is P(X = 0) when $n = 10$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.3487$

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

8 0

3 years ago

Look at the system of equations below.

Annette [7]

Answer:

Substitution and graphing are less efficient methods than elimination for this system as there is extra amount of steps we have to take to solve the same system of equations - hence time consuming and a margin or error may happen. Therefore, elimination is the suitable method for solving this system.

Step-by-step explanation:

Let us consider the system of equation below.

$4x-5y=3$

$3x+5y=13$

Elimination method sounds the most appropriate option to solve the given system of equations as we can easily sort out an equation in one variable x in minimal steps by just adding the both equations as the y-coefficient in the first equation is the opposite of the y-coefficient in the second equation, and we can determine an equation in one variable x.

Adding both equations will eliminate the y-variable and we can easily sort out the value of x from the resulting equation.

As the given system of equation

$4x-5y=3$ $......[1]$

$3x+5y=13$ $......[2]$

Adding Equation 1 and Equation 2

$4x-5y+3x+5y=3+13$

$7x=16$

$x=$ $\frac{16}{7}$

Putting $x=$ $\frac{16}{7}$ in Equation [1]

$4x-5y=3$ $......[1]$

$y=$ $\frac{43}{35}$

Although substitution or graphing methods can also be used to bring the solution of the given system of equations, but using substitution or graphing method can be sometimes cumbersome or time-consuming as it would have to take some additional steps to solve the system.

For example, if we would have to use the substitution methods to solve the given system of equations, first we would have to solve one of the equations by choosing one of the equation for one of the chosen variables and then putting this back into the other equation, and solve for the other, and then back-solving for the first variable.

As the given system of equation

$4x-5y=3$ $......[1]$

$3x+5y=13$ $......[2]$

Solving the equation 2 for x variable

$3x=13-5y$

$x=\frac{13-5y}{3}$

Plugging $x=\frac{13-5y}{3}$ in equation [1]

$4(\frac{13-5y}{3}) -5y=3$

$y = \frac{43}{35}$

Putting $y = \frac{43}{35}$ in Equation 2

$3x+5y=13$ $......[2]$

$x = \frac{16}{7}$

So, you can figure out, we have to make additional steps when we use substitution method to solve this system of equations.

Similarly, using graphing method, it would take a certain time before we identify the solution of the system.

Hence, from all the discussion and analysis we did, we can safely say that substitution and graphing are less efficient methods than elimination for this system as there is extra amount of steps we have to take to solve the same system of equations - hence time consuming and a margin or error may happen.

Therefore, we agree with the student argument that Elimination is the best method for solving this system because the y-coefficient in the first equation is the opposite of the y-coefficient in the second equation.

Keywords: substitution method, system of equations, elimination method

Lear more about elimination method of solving the system of equation from brainly.com/question/12938655

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4 0

3 years ago

Need an answer, please need an answer, please

trasher [3.6K]

Answer:

Step-by-step explanation:

Area = 192 m²

Perimeter= 56 m

Width = x m

Perimeter = 56

2*(length + width) = 56

Divide the equation by 2

l + x = 56/2

l + x = 28

l = 28 - x

Area = 192 m²

l * w = 192

(28 - x)*x = 192

28x - x*x = 192

0 = 192 - 28x + x²

x² - 28x + 192 = 0

2) Equation is a quadratic equation. The roots of this equation will the dimensions of the rectangular plot.

3) The roots represent the width and length of the rectangle.

x² - 28x +192 = 0

Sum = -28

Product =192

Factors = -16 , -12 {-16 +(-12) = -28 & (-12)*(-16) = 192}

x² - 28x + 192 = 0

x² - 12x - 16x + (-16)*(-12) = 0

x(x -12) - 16(x - 12) = 0

(x - 12)(x -16) =0

x -12 = 0 ; x - 16 = 0

x = 12 ; x = 16

x = 12 ,16

4) Sum of the roots = 12 + 16 = 28

Sum of the roots = half of the perimeter

5) Product of the roots = 12*16 = 192 = area of the rectangle.

6 0

2 years ago