Answer:
8192
Step-by-step explanation:
The pattern here is that each term multiplied by 4 is the next number. You can keep multiplying by 4 until you reach the 7th term. So the 5th term will be 128x4 = 512. The 6th term will the 512x4 = 2048. And finally, the 7th term will be 2048x4 = 8192.
Answer:
8
Step-by-step explanation:
12-8=4
4 times 2 =8
F(3)=53 and for f(x)=1; x=2
Answer:
if you mulitply (19*19*27*10*10) you get:
974700
Step-by-step explanation:
Given:
- Length of the Rectangle is 3 more than its width.
- Perimeter of rectangle is 54 m
To Find:
- Length and Breadth
- Area of the rectangle
Solution:
We are given length of a rectangle is 3 more than its width
Let's assume:
- Breadth of the rectangle = x
- Length of the rectangle = x + 3
We know that,
![\dashrightarrow \sf \: \: Perimeter_{(rectangle)} = 2(L + B)](https://tex.z-dn.net/?f=%5Cdashrightarrow%20%5Csf%20%5C%3A%20%5C%3A%20Perimeter_%7B%28rectangle%29%7D%20%3D%202%28L%20%2B%20B%29%20)
![\dashrightarrow \sf \: \: 54 = 2(x + x + 3)](https://tex.z-dn.net/?f=%5Cdashrightarrow%20%5Csf%20%5C%3A%20%5C%3A%2054%20%3D%202%28x%20%2B%20x%20%2B%203%29%20)
![\dashrightarrow \sf \: \: 54 = 2(2x + 3)](https://tex.z-dn.net/?f=%5Cdashrightarrow%20%5Csf%20%5C%3A%20%5C%3A%2054%20%3D%202%282x%20%2B%203%29)
![\dashrightarrow \sf \: \: \dfrac{54}{2} = 2x + 3](https://tex.z-dn.net/?f=%5Cdashrightarrow%20%5Csf%20%5C%3A%20%5C%3A%20%5Cdfrac%7B54%7D%7B2%7D%20%3D%202x%20%2B%203)
![\dashrightarrow \sf \: \: 27 = 2x + 3](https://tex.z-dn.net/?f=%5Cdashrightarrow%20%5Csf%20%5C%3A%20%5C%3A%2027%20%3D%202x%20%2B%203)
![\dashrightarrow \sf \: \: 27 - 3 = 2x](https://tex.z-dn.net/?f=%5Cdashrightarrow%20%5Csf%20%5C%3A%20%5C%3A%2027%20-%203%20%3D%202x%20)
![\dashrightarrow \sf \: \: 24 = 2x](https://tex.z-dn.net/?f=%5Cdashrightarrow%20%5Csf%20%5C%3A%20%5C%3A%20%2024%20%3D%202x%20)
![\dashrightarrow \sf \: \: \dfrac{24}{2} = x](https://tex.z-dn.net/?f=%5Cdashrightarrow%20%5Csf%20%5C%3A%20%5C%3A%20%5Cdfrac%7B24%7D%7B2%7D%20%3D%20x%20)
![\dashrightarrow \: \: {\underline{\boxed{\pink{\pmb{\mathfrak{12 = x}}}}}}](https://tex.z-dn.net/?f=%5Cdashrightarrow%20%5C%3A%20%5C%3A%20%7B%5Cunderline%7B%5Cboxed%7B%5Cpink%7B%5Cpmb%7B%5Cmathfrak%7B12%20%3D%20x%7D%7D%7D%7D%7D%7D%20)
Hence,
- Breadth of rectangle = x = 12 m
- Length of rectangle = 3 + x = 15 m
<u>Now, Finding its area</u>:
![\dashrightarrow \: \: { \sf{ Area_{(rectangle)} = L \times B }} \: \\](https://tex.z-dn.net/?f=%5Cdashrightarrow%20%20%5C%3A%20%20%5C%3A%20%7B%20%5Csf%7B%20Area_%7B%28rectangle%29%7D%20%3D%20L%20%5Ctimes%20B%20%7D%7D%20%5C%3A%20%20%20%5C%5C%20)
![\dashrightarrow \sf \: \: Area = 12 \times 15](https://tex.z-dn.net/?f=%5Cdashrightarrow%20%5Csf%20%5C%3A%20%5C%3A%20Area%20%3D%2012%20%5Ctimes%2015%20)
![\dashrightarrow \sf \: \: {\underline{\boxed{\pink{\pmb{\mathfrak{Area = 180 \: {m}^{2}}}}}}}](https://tex.z-dn.net/?f=%5Cdashrightarrow%20%5Csf%20%5C%3A%20%5C%3A%20%7B%5Cunderline%7B%5Cboxed%7B%5Cpink%7B%5Cpmb%7B%5Cmathfrak%7BArea%20%3D%20180%20%20%20%5C%3A%20%7Bm%7D%5E%7B2%7D%7D%7D%7D%7D%7D%7D%20)
<u>Hence</u>,
- Length and breadth of rectangle is 12 m and 15 m
- Area of the rectangle is 180 m²