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jekas [21]
3 years ago
10

Which of the following elements is a transition metala. Lab. CaC. Cld. Mn​

Chemistry
1 answer:
nlexa [21]3 years ago
7 0

Answer:

La is a transition metal

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12. How many moles of atoms are present in 154 g of Na2O?
tia_tia [17]

Answer:

\boxed {\boxed {\sf A. \ 2.48 \ mol \ Na_2O}}

Explanation:

We are asked to convert an amount in grams to moles. To do this, we use the molar mass. This is the number of grams in one mole of a substance. It is the same value numerically as the atomic mass on the Periodic Table, however the units are grams per mole, not atomic mass units.

Look up the molar masses for the individual elements.

  • Sodium (Na): 22.9897693 g/mol
  • Oxygen (O): 15.999 g/mol

Look back at the formula: Na₂O. Notice there is a subscript of 2 after sodium. This means there are 2 atoms of sodium in every molecule, so we have to multiply sodium's molar mass by 2 before adding oxygen's.

  • Na₂O: 2(22.9897693 g/mol)+ 15.999 g/mol = 61.9785386 g/mol

Set up a ratio using the molar mass.

\frac {61.9785386 \ g \ Na_2O}{1 \ mol \ Na_2O}

Multiply by the given number of grams.

154 \ g \ Na_2O*\frac {61.9785386 \ g \ Na_2O}{1 \ mol \ Na_2O}

Flip the ratio so the grams of sodium oxide can cancel each other out.

154 \ g \ Na_2O*\frac {1  \ mol \ Na_2O}{61.9785386 \ g \ Na_2O}

154 *\frac {1  \ mol \ Na_2O}{61.9785386 }

\frac {154}{61.9785386 }  \ mol \ Na_2O

2.48473106141 \ mol \ Na_2O

The original measurement of grams given has 3 significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place.

  • 2.48<u>4</u>73106141

The 4 in the thousandth place tells us to leave the 8.

2.48 \ mol \ Na_2O

There are <u>2.48 moles of sodium oxide</u> in 154 grams, so choice A is correct.

6 0
3 years ago
Which element is best known for it's bad smell?
tia_tia [17]
The bad smelling element is Sulfur, which smells like rotting eggs.
5 0
3 years ago
What are the characteristics of an extrusive rock
olya-2409 [2.1K]

Extrusive Rocks. Igneous rocks which form by the crystallization of magma at the surface of the Earth are called extrusive rocks. They are characterized by fine-grained textures because their rapid cooling at or near the surface did not provide enough time for large crystals to grow.

5 0
4 years ago
Refrigerant-134a enters the coils of the evaporator of a refrigeration system as a saturated liquid-vapor mixture at a pressure
Firdavs [7]

Answer:

(a) 0.699 kJ/K

(b) -0.671 kJ/K

(c) 0.028 kJ/K

Explanation:

The Refrigerant-134a flows into the evaporator as a saturated liquid-vapor mixture and flows out as a saturated vapor at a saturation pressure of 160 kPa and temperature of -15.64°C (estimated from the Saturated Refrigerant-134a Temperature Table).

(a) The entropy change of the refrigerant (ΔS_{R-134a}) = Q/T_{1}

Q = 180 kJ

T_{1} = -15.64 + 273.15 = 257.51 K

ΔS_{R-134a} = Q/T_{1} = 180/257.51 = 0.699 kJ/K

(b) The entropy change (ΔS_{c}) of the cooled space (ΔS_{c}) = -Q/T_{2}

Q = -180 kJ

T_{2} = -5 + 273.15 = 268.15 K

ΔS_{c} = Q/T_{2} = -180/268.15 = -0.671 kJ/K

(c) The total entropy change for this process (ΔS_{t}) = ΔS_{R-134a} + ΔS_{c} = 0.699 - 0.671 = 0.028 kJ/K

6 0
3 years ago
Please help me thank you.
Semmy [17]
I will show you with detailed work for NaCl, but follow the same procedure for the rest of the compounds.

Molar Mass - Find the molar mass of the Na and the Cl and add them together
Na - 23
Cl - 35.5
Add those numbers together 23 + 35.5 = 58.5 g/mol

Moles in 1 tsp:
The mass measured in 1tsp of NaCl was 18 g.  To calculate the amount of moles you take the mass measured and divide it by the molecular weight.
18/58.5 = 0.3077 mol

Moles of each element:
To find the moles each element in the compound you multiply the moles of 1 tsp by the number of atoms of the element in the compound
Na - 1 in NaCl
Cl - 1 in Na Cl
so take 0.3077 * 1 = 0.3077 moles Na (and Cl in this case)

Atoms of each:
take the number of moles calculated and multiply that by Avogadro's number(6.023x10^23) for the number of molecules
So for both Na and Cl:
0.3077 * 6.023x10^23 = 1.853x10^23 atoms for both Na and Cl
7 0
4 years ago
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