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Andreyy89
3 years ago
5

BONUS QUESTION - It takes 194 mL of a 0.5 M NaOH solution to neutralize 300

Chemistry
1 answer:
Strike441 [17]3 years ago
6 0

Answer:

1.7 mol/dm3

Explanation:

working out in the image

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A piece of tin has a mass of 16.52 g and a volume of 2.26 cm3 what is the density of tin?
boyakko [2]

Answer:

The density of tin is 7.31 g/cm³.

Explanation:

Given that the formula of density is D = m/v where m represents mass and v is volume :

D = 16.52/2.26

D = 7.31 g/cm³ (3sf)

7 0
3 years ago
When a 18.0 mL sample of a 0.308 M aqueous hydrofluoric acid solution is titrated with a 0.361 M aqueous sodium hydroxide soluti
sleet_krkn [62]

Answer:

pH = 12.8

Explanation:

HF + NaOH → F⁻ + Na⁺ + H₂O

<em>1 mole of HF reacts with 1 mole of NaOH</em>

<em />

Initial moles of HF and NaOH are:

HF = 0.018L × (0.308mol / L) = 5.544x10⁻³mol HF

NaOH = 0.023L × (0.361mol / L) = 8.303x10⁻³mol NaOH

That means moles of NaOH remains after reaction are:

8.303x10⁻³mol - 5.544x10⁻³mol = <em>2.759x10⁻³moles NaOH</em>

Total volume is 18.0mL + 23.0mL = 41.0mL = 0.0410L

Molar concentration of NaOH is

2.759x10⁻³moles NaOH / 0.0410L = 0.0673M = [OH⁻]

pOH = - log [OH⁻] = 1.17

As pH = 14 - pOH

<em>pH = 12.8</em>

<em></em>

4 0
3 years ago
During the third stage of labor what happens? (it's not C)
QveST [7]

Answer:

B

Explanation:

placenta comes after baby

5 0
2 years ago
The electron ____ of an element shows the arrangement of electrons within an atom
Verdich [7]
The electron ring dors
7 0
3 years ago
Which condition increases the number of collisions between reactant molecules in a given volume?
Nezavi [6.7K]

Answer:

Increasing Surface Area

Explanation:

A greater surface area (meaning more, smaller particles) allows for more opportunity for particles to collide.  On the other hand, decreasing temperature and removing a catalyst would only decrease the number of collisions, and the clumping option doesn't make much sense.  Hope this helps!

4 0
3 years ago
Read 2 more answers
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