1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kompoz [17]
3 years ago
7

the volume of a gas is 250mL at 340.0kPa pressure. what will the volume be when the pressure is reduced to 50.0kPa assuming the

temperature remains constant
Chemistry
1 answer:
ki77a [65]3 years ago
6 0

Clearly volume will INCREASE almost sevenfold, as we would expect if we reduce the pressure. ... Assuming this is an ideal gas, and that the number of molecules *n* of this gas remains constant, and given that the temperature is also ... That is, in these conditions, pressure times volume is constant :


You might be interested in
8SnCl4<br> How many atoms
Veronika [31]

Answer:

i think i like 14 or 8 atom

Explanation:

8 0
3 years ago
Determine the freezing point of an aqueous solution containing 10.50 g of magnesium bromide in 200.0 g of water.
Rudiy27
For an aqueous solution of MgBr2, a freezing point depression occurs due to the rules of colligative properties. Since MgBr2 is an ionic compound, it acts a strong electrolyte; thus, dissociating completely in an aqueous solution. For the equation:

                                ΔTf<span> = (K</span>f)(<span>m)(i)
</span>where: 
ΔTf = change in freezing point = (Ti - Tf)
Ti = freezing point of pure water = 0 celsius
Tf = freezing point of water with solute = ?
Kf = freezing point depression constant = 1.86 celsius-kg/mole (for water)
m = molality of solution (mol solute/kg solvent) = ?
i = ions in solution = 3

Computing for molality:
Molar mass of MgBr2 = 184.113 g/mol

m = 10.5g MgBr2 / 184.113/ 0.2 kg water = 0.285 mol/kg


For the problem, 
ΔTf = (Kf)(m)(i) = 1.86(0.285)(3) = 1.59 = Ti - Tf = 0 - Tf

Tf = -1.59 celsius
5 0
3 years ago
The half-life of cesium-137 is 30 years. suppose we have a 200-mg sample.
Assoli18 [71]
a) To find  the mass after t years:

we will use this formula:

A = Ao / 2^n 

when A =the amount remaining

and Ao = the initial amount

and n = t / t(1/2)

by substitution:

∴ A = 200 mg/ 2^(t/30y)


b) Mass after 90 y :

by  using the previous formula and substitute t by 90 y

A = 200mg/ 2^(90y/30y)

∴ A = 25 mg

C) Time for 1 mg remaining:

when A= Ao/ 2^(t/t(1/2)

so, by substitution:

1 mg = 200 mg / 2^(t/30y)

∴2^(t/30y) = 200 mg  by solving for t

∴ t = 229 y 


7 0
3 years ago
Consider separate 1.0-L samples of He(g) and UF6(g), both at 1.00 atm and containing the same number of moles. What ratio of tem
diamong [38]
V =  \sqrt{x} 3 * R * T / MW

V = RMS velocity

R = 8.3145 J/K*mole

T = Temperature K

MW = Molecular weigh in Kg
3 0
3 years ago
The atom shown below is?
Volgvan

Answer:

Explanation:

Not likely to form any bonds because in it's last she'll it has 8 electrons and is therefore stable

8 0
3 years ago
Other questions:
  • Complete this equation for the dissociation of K3PO4(aq). Omit water from the equation because it is understood to be present.
    9·2 answers
  • Make the conversion indicated ineach of the following:
    13·1 answer
  • Lol nevermind i figured it out
    8·1 answer
  • Why is hydrogen not part of an alkali metal?
    13·1 answer
  • If white light shines on an object and the red, orange, green, blue, indigo, and violet light is absorbed. What color does your
    11·2 answers
  • What kind of rocks are formed by the precipitation of calcium carbonate (CaCO3) from sea water? Select all that apply.
    12·1 answer
  • 2.<br> Number that indicates the charge for each family.
    9·1 answer
  • How do particles differ after a physical change?
    13·1 answer
  • What is the uncertian digit in 0.054 g
    15·1 answer
  • Doy CORONITA a quien me ayude rapido que es un examen porfaaa
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!