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kompoz [17]
3 years ago
7

the volume of a gas is 250mL at 340.0kPa pressure. what will the volume be when the pressure is reduced to 50.0kPa assuming the

temperature remains constant
Chemistry
1 answer:
ki77a [65]3 years ago
6 0

Clearly volume will INCREASE almost sevenfold, as we would expect if we reduce the pressure. ... Assuming this is an ideal gas, and that the number of molecules *n* of this gas remains constant, and given that the temperature is also ... That is, in these conditions, pressure times volume is constant :


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A titration was performed in a lab situation. H2SO4 was titrated with NaOH. The following data was collected: mL of NaOH used =
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For the titration we use the equation,
                             M₁V₁ = M₂V₂
where M is molarity and V is volume. Substituting the known values,
                            (0.15 M)(43.2 mL) = (2)(M₂)(20.5 mL)
We multiply the right term by 2 because of the number of H+ in H2SO4. Calculating for M₂ will give us 0.158 M. Thus, the answer is approximately 0.16M. 
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The standard length of a certain golf club is 116.84 cm. You measure the club to be 116.85 cm long. You measure it again and fin
IgorC [24]

Answer:

The first measurement is 116.84 cm, and the second measurement is 116.85 cm.

Explanation:

The problem provides both the first and second measurements so all you have to do is fill in the blank with them.

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3 years ago
The key enzyme in the regulation of the citric acid cycle is:.
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The key enzyme in the regulation of the citric acid cycle is citrate synthase. It functions in the mitochondria.

<h3>Citrate synthase and cellular respiration </h3>

Cellular respiration is a series of reactions that produce ATP by using the energy stores in the chemical bonds of foods.

Cellular respiration is divided into glycolysis, the citric-acid cycle and oxidative phosphorylation.

Citrate synthase is an enzyme found in the mitochondrial matrix, which is involved in the citric acid cycle.

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3 0
2 years ago
Classify the outcomes based on whether they are caused by adding or removing a reactant from a chemical reaction. The rate of th
Mama L [17]

Explanation: To study the outcomes, we will apply Le-Chatelier's principle.

Le-Chatelier's principle states that if there is any disturbance in the conditions of the dynamic equilibrium, the position of equilibrium will counteract the change.

1) The rate of the forward reaction increases.

This will happen when we add the reactant to a chemical reaction. According to Le-Chatelier's principle, by increasing the reactant, the equilibrium will shift in the direction where this effect is minimal. Hence, forward reaction is favored.

2) The rate of the revere reaction increases.

This will happen when we remove the reactant from a chemical reaction. According to Le-Chatelier's principle, by removing the reactant, the equilibrium will shift in the direction where this effect is minimal. Hence, reverse reaction is favored.

3) The concentration of product increases.

This will happen when we add reactants to a chemical reaction. According to  Le-Chatelier's principle, when we increase the concentration of reactants, the equilibrium will shift in the direction where this effect is minimal. Hence, the reaction will be in the forward direction which means that the concentration of product will increase.

4) The concentration of products decreases.

This will happen when we remove reactants from a chemical reaction. According to  Le-Chatelier's principle, when we decrease the concentration of reactants, the equilibrium will shift in the direction where this effect is minimal. Hence, the reaction will be in the reverse direction which means that the concentration of reactants will increase or concentration of products will decrease.

3 0
3 years ago
Glycolic acid, which is a monoprotic acid and a constituent in sugar cane, has a pKa of 3.9. A 25.0 mL solution of glycolic acid
Phoenix [80]

Answer:

pH = 8.0

Explanation:

First, we have to calculate the moles of NaOH.

35.8 \times 10^{-3}L.\frac{0.020mol}{L} =7.2\times 10^{-4}mol

Let's consider the balanced equation.

C₂H₄O₃ + NaOH ⇒ C₂H₃O₃Na + H₂O

The molar ratio C₂H₄O₃: NaOH: C₂H₃O₃Na is 1: 1: 1. So, when 7.2 × 10⁻⁴ moles of NaOH react completely with 7.2 × 10⁻⁴ moles of C₂H₄O₃ they form 7.2 × 10⁻⁴ moles of C₂H₃O₃Na.

The concentration of C₂H₃O₃Na is:

\frac{7.2\times 10^{-4}mol}{60.8 \times 10^{-3}L} =0.012M

C₂H₃O₃Na dissociates according to the following equation:

C₂H₃O₃Na(aq) ⇒ C₂H₃O₃⁻(aq) + Na⁺(aq)

C₂H₃O₃⁻ comes from a weak acid so it undergoes basic hydrolisis.

C₂H₃O₃⁻ + H₂O ⇄ C₂H₄O₃ + OH⁻

If we know that pKa for C₂H₄O₃ is 3.9, we can calculate pKb for C₂H₃O₃⁻ using the following expression:

pKa + pKb = 14

pKb = 14 -3.9 = 10.1

10.1 = -log Kb

Kb = 7.9 × 10⁻¹¹

We can calculate [OH⁻] using the following expression:

[OH⁻] = √(Kb.Cb)               <em>where Cb is the initial concentration of the base</em>

[OH⁻] = √(7.9 × 10⁻¹¹ × 0.012M) = 9.7 × 10⁻⁷ M

Now, we can calculate pOH and pH.

pOH = -log [OH⁻] = -log (9.7 × 10⁻⁷) = 6.0

pH + pOH = 14

pH = 14 - pOH = 14 - 6.0 = 8.0

7 0
3 years ago
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