The statements that are true are;
- the magnitude of work done by frictional forces on the crate is 100 J
- the magnitude of work done by the applied force on the crate is 100 J
<h3>What is work done?</h3>
Work is said to be done when te force applied travels a distance in the direction of the force. Now we can see that when the force is applied by shoving the crate, work is done, an additional work is done by friction to bring the crate to a stop.
Hence, the following are true;
- the magnitude of work done by frictional forces on the crate is 100 J
- the magnitude of work done by the applied force on the crate is 100 J
Learn more about work: brainly.com/question/18094932?
Answer:
a). P=11.04kW
b). Pmax=11.38 kW
c). Wt=6423.166kJ
Explanation:
The power of the motor when the speed is constant is the work in a determinate time.

The work is the force the is applicated in a distance so
W=F*d
replacing:
and
determinate distance in time is velocity so
a).


b).
The maximum power must the motor provide, is the maximum force with the maximum speed of the motor in this case
The first step is find the acceleration so

The maximum force is when the car is accelerating so

so the maximum force is the maximum force by the maximum speed

c).
The total energy transfer without any friction is the weight move in the high axis y in this case, so is easy to know that distance
W=m*g*h
h=Length*sin(33.5)
W=m*g*Length*sin(33.5)
W=950 kg*9.8* 1250m*sin(33.5)
W=6423166.667 kJ
W=6423.166 kJ
Voltage, resistance and current are the three components that must be present for a circuit to exist. A circuit will not be able to function without these three components. Voltage is the main electrical source that is present in a circuit. :)
Answer:
q = 1.815 \times 10^{-8} C
Charge on one plate is positive in nature and on the other plate it is negative in nature.
Explanation:
E = 8.20 x 10^5 V/m, A = 25 cm^2, d = 22.45 mm
According to the Gauss's theorem in electrostatics
The electric field between the two plates




Charge, q = surface charge density x area

q = 1.815 \times 10^{-8} C