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kirill [66]
3 years ago
7

A charged particle is surrounded by an electric field and a magnetic field

Physics
2 answers:
zlopas [31]3 years ago
7 0

Answer:

yeah

Explanation:

electric fields help the charged particles interact

and isn't magnetic field the same as electric field.

mihalych1998 [28]3 years ago
7 0
A charged particle is surrounded by an electric field (E field), but no magnetic field. When the particle moves, the changing electric field induces a magnetic field: this is one of the Maxwell Equations (Ampère’s Law)
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A 16 Ω resistor and a 6 Ω resistor are connected in series to an ideal 6 V battery.
GrogVix [38]

Answer:

Explanation:

a) series resistors carry the same current

A = V/Re = 6/(16 + 6) = 0.2727272... ≈ 27 mA

b) V = V₀(R/Re) = 6(16/(16 + 6)) = 4.363636 ≈ 4.4 V

c) V = V₀(R/Re) = 6(6/(16 + 6)) = 1.636363 ≈ 1.6 V

 or V = 6 - 4.4 = 1.6 V

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3 years ago
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Follow stop drop and roll if the fire is in the room
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3 years ago
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What type of solar radiation does not reach the surface of the earth?
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3 years ago
A driven RLC circuit is being driven by an AC emf source with a maximum current of 2.75 A and maximum voltage of 150 V. The curr
weqwewe [10]

Answer:

(a). Z = 54.54 ohm

(b). R = 36 ohm

(c). The circuit will be Capacitive.

Explanation:

Given data

I = 2.75 A

Voltage = 150 V

\phi = 0.85 rad = 48.72°

(a). Impedance of the circuit is given by

Z = \frac{V}{I}

Z = \frac{150}{2.75}

Z = 54.54 ohm

(b). We know that resistance of the circuit is given by

R = \frac{Z}{\sqrt{1 + \tan^{2}\phi } }

Put the values of Z & \phi in above formula we get

R = \frac{54.54}{\sqrt{1 + \tan^{2} ( \ 48.72) } }

R = 36 ohm

(c). Since the phase angle is negative so the circuit will be Capacitive.

3 0
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