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3 years ago

What is the average speed of a car that moved 40 km in 3 hours?

Physics

1 answer:

Naya [18.7K]3 years ago

3 0

A would be the answer, since it would take about 3 hours to cover most of it, 10km/h would be the average speed.

really hope this helps.

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What happens to the composition of an atom to cause it to become positively or negatively charged?

Usimov [2.4K]

An atom gains one or more electrons and becomes negatively charged, or loses one or more electrons and becomes positively charged.

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3 years ago

The purpose of this piece of equipment is to

frozen [14]

A. Because that is a digital balance

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4 years ago

Two slits separated by a distance of d = 0.190 mm are located at a distance of D = 1.91 m from a screen. The screen is oriented

Svetlanka [38]

Answer:

$\theta = 0.195^0$

Explanation:

wavelength $\lambda = 648 nm \ = 648*10^{-9}m$

d = 0.190 mm = 0.190 × 10⁻³ m

D = 1.91 m

By using the formula:

$dsin \theta = n \lambda\\\\\theta = sin^{(-1)}(\frac{n \lambda}{d})\\\\\\\theta = sin^{(-1)}(\frac{1*648*10^{-9}}{0.190*10^{-3}})$

$\theta = 0.195^0$

The first maximum will appear at an angle $\theta = 0.195^0$ from the beam axis

3 0

3 years ago

A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 10 m from the takeoff point. you may want t

Stells [14]

Answer:

Takeoff speed of Kangaroo = 12.91 m/s

Explanation:

The distance reached by Kangaroo = 10 meter

Angle at which it jumps = 18°

The motion of Kangaroo is like a projectile, the distance traveled is the range of projectile.

Range of projectile = Time taken for the projectile to reach ground* Horizontal velocity

Time taken for the projectile to reach ground:

Time taken = Two times of the time taken for the projectile to reach maximum height

Time taken for the projectile to reach maximum height = Vertical speed / Acceleration = u sin θ/g

Time taken for the projectile to reach ground = 2 u sin θ/g

So Range of projectile = $ucos\theta*\frac{2usin\theta}{g} =\frac{u^2sin2\theta}{g}$

We have Range = 10 meter, θ = 18⁰

Substituting

$10=\frac{u^2sin(2*18)}{9.8}\\ \\ u^2= 166.73\\ \\ u=12.91 m/s$

Takeoff speed of Kangaroo = 12.91 m/s

3 0

3 years ago

Read 2 more answers

Question 2: What is the velocity ratio of this pulley?

Vladimir [108]

Answer:

1/3

Explanation:

Velocity ratio = distance moved by effort / distance moved by load

3 0

3 years ago