Answer:
the diameter of the second pipe is 2.52 in
Explanation:
Given the data in the question;
We know that; the rate of flow is the same;
so
Av1 = Av2
v ∝ √h
= 
= √( 
)
( π/4.D1² / π/4.D2² ) = √( )
( D1² / D2² ) = √( 
) since second is double of first
so
( D1² / D2² ) = √( 
)
3² / D2² = √2
D2²√2 = 9
D2² = 9/√2
D2² = 9 / 1.4142
D2² = 6.364
D2 = √ 6.364
D2 = 2.52 in
Therefore, the diameter of the second pipe is 2.52 in
Answer:
v/c = 0.76
Explanation:
Formula for Length contraction is given by;
L = L_o(√(1 - (v²/c²))
Where;
L is the length of the object at a moving speed v
L_o is the length of the object at rest
v is the speed of the object
c is speed of light
Now, we are given; L = 65%L_o = 0.65L_o, since L_o is the length at rest.
Thus;
0.65L_o = L_o[√(1 - (v²/c²))]
Dividing both sides by L_o gives;
0.65 = √(1 - (v²/c²))
Squaring both sides, we have;
0.65² = (1 - (v²/c²))
v²/c² = 1 - 0.65²
v²/c² = 0.5775
Taking square root of both sides gives;
v/c = 0.76
Answer:
No
Explanation:
All planets are different than others and bigger so that means no
Answer: e. P/2
Explanation:
For ideal gases, we have the relation:
P*V = n*R*T
where:
n = number of mols
R = Gas constant
T = temperature
V = volume
P = pressure.
We know that for sample A, we have n moles, a temperature T and a volume V, then the pressure of this sample will be:
Pa = (n*R*T)/V.
For sample B, we have:
n/2 moles, temperature T/2 and a volume V/2, then the pressure will be:
Pb = (n/2)*R*(T/2)*(2/V) = (n*R*T/V)*(2/4)
and:
(n*R*T/V) = Pa
Then we can replace it and we get:
Pb = (n*R*T/V)*(2/4) = Pa*(2/4) = Pa*(1/2) = Pa/2.
Then the correct option is e.
It’s light seconds, now don’t mistake it as time
