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goldfiish [28.3K]
3 years ago
15

What 4 divided by 1/10??

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
3 0
1. Turn 4 into a fraction --> 4/1

2. Divide 4/1 by 1/10 by switching 1/10 upside down and multiplying 4/1 by it:

    4/1 x 10/1 --> Carry out the multiplication. Multiply the numerators together     and the denominators together.

4/1 x 10/1 = 40/1
Convert 40/1 into decimal form =
<u>40</u>
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alex41 [277]
Well all u have to do is minus -6 from 23 so 23-6 is 17. Then all u have to do is add 0+17 so ur answer is the temperature changed 17 F
8 0
3 years ago
Hello!!! i’ll give brainliest if you want but please answer correctly
Leya [2.2K]

Answer:

Chaos

Lack of understanding for how to behave

Disregard for other people

Step-by-step explanation:

8 0
3 years ago
The area of the trapezoid is 108 in2.<br><br> What is the height of the trapezoid?
dezoksy [38]

The area of the trapezoid is given by the formula A= (a+b)/ 2 * h

in this question a= 8, b= 10, A= 108 inches², and h is what we have to find, substitute what we have got into the formula and you will have:

108= (8+10) /2 *h

108= 9 *h

h= 108/9

h= 12 inches



5 0
3 years ago
Read 2 more answers
Integrate sin^-1(x) dx<br><br> please explain how to do it aswell ...?
Lynna [10]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2264253

_______________


Evaluate the indefinite integral:

\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx\qquad\quad\checkmark}


Trigonometric substitution:

\mathsf{\theta=sin^{-1}(x)\qquad\qquad\dfrac{\pi}{2}\le \theta\le \dfrac{\pi}{2}}


then,

\begin{array}{lcl} \mathsf{x=sin\,\theta}&\quad\Rightarrow\quad&\mathsf{dx=cos\,\theta\,d\theta\qquad\checkmark}\\\\\\ &&\mathsf{x^2=sin^2\,\theta}\\\\ &&\mathsf{x^2=1-cos^2\,\theta}\\\\ &&\mathsf{cos^2\,\theta=1-x^2}\\\\ &&\mathsf{cos\,\theta=\sqrt{1-x^2}\qquad\checkmark}\\\\\\ &&\textsf{because }\mathsf{cos\,\theta}\textsf{ is positive for }\mathsf{\theta\in \left[\dfrac{\pi}{2},\,\dfrac{\pi}{2}\right].} \end{array}


So the integral \mathsf{(ii)} becomes

\mathsf{=\displaystyle\int\! \theta\,cos\,\theta\,d\theta\qquad\quad(ii)}


Integrate \mathsf{(ii)} by parts:

\begin{array}{lcl} \mathsf{u=\theta}&\quad\Rightarrow\quad&\mathsf{du=d\theta}\\\\ \mathsf{dv=cos\,\theta\,d\theta}&\quad\Leftarrow\quad&\mathsf{v=sin\,\theta} \end{array}\\\\\\\\ \mathsf{\displaystyle\int\!u\,dv=u\cdot v-\int\!v\,du}\\\\\\ \mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta-\int\!sin\,\theta\,d\theta}\\\\\\ \mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta-(-cos\,\theta)+C}

\mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta+cos\,\theta+C}


Substitute back for the variable x, and you get

\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx=sin^{-1}(x)\cdot x+\sqrt{1-x^2}+C}\\\\\\\\ \therefore~~\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx=x\cdot\,sin^{-1}(x)+\sqrt{1-x^2}+C\qquad\quad\checkmark}


I hope this helps. =)


Tags:  <em>integral inverse sine function angle arcsin sine sin trigonometric trig substitution differential integral calculus</em>

6 0
3 years ago
What is the value of 7x²-10, when x = 6? please help me will mark<br> brainliest
vodka [1.7K]

Step-by-step explanation:

7(6^2)-10

=7×36-10

=252-10

242

3 0
3 years ago
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