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3 years ago

2 Points

Physics

2 answers:

malfutka [58]3 years ago

8 0

Answer:

A. 0.32 s

Explanation:

The other answer did the math wrong but came up with the same answer. Anyway, you're supposed to use sin.

4sin(23) gives you 1.56 or 1.6

-1.56/-9.8 (negative because gravity is working against the direction of of the athlete as he goes into the air) = 0.159...

0.159*2 = 0.318

Round: 0.32

Tamiku [17]3 years ago

6 0

Answer:

A. 0.32s

Explanation:

Lets find the initial velocity of the vertical component

Cos23=u/4

4cos23=1.6m/s

then time, t =2u/g

2×1.6/9.8

=0.32seconds

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The magnitude of the drills angular acceleration is $-32\pi s^{-2}$ .

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