Answer:
-16
Step-by-step explanation:
10 x -1= -10
2 x -2= -4
-10-4= -14
-14-2= -16
Answer:
f(x)=-18x^2
Step-by-step explanation:
Given:
1+Integral(f(t)/t^6, t=a..x)=6x^-3
Let's get rid of integral by differentiating both sides.
Using fundamental of calculus and power rule(integration):
0+f(x)/x^6=-18x^-4
Additive Identity property applied:
f(x)/x^6=-18x^-4
Multiply both sides by x^6:
f(x)=-18x^-4×x^6
Power rule (exponents) applied"
f(x)=-18x^2
Check:
1+Integral(-18t^2/t^6, t=a..x)=6x^-3
1+Integral(-18t^-4, t=a..x)=6x^-3
1+(-18t^-3/-3, t=a..x)=6x^-3
1+(6t^-3, t=a..x)=6x^-3
That looks great since those powers are the same on both side after integration.
Plug in limits:
1+(6x^-3-6a^-3)=6x^-3
We need 1-6a^-3=0 so that the equation holds true for all x.
Subtract 1 on both sides:
-6a^-3=-1
Divide both sides by-6:
a^-3=1/6
Raise both sides to -1/3 power:
a=(1/6)^(-1/3)
Negative exponent just refers to reciprocal of our base:
a=6^(1/3)
Answer:
1. y + 10 - 3/2y = -y/2 + 10
2. 2r+ 7r-r - 9 = 8r - 9
3. 7 + 4p-5+p+2q = 2 + 5p + 2q
Step-by-step explanation:
basically you can add terms that have the same variable
integers can be added together, Xs can be added, Zs, Ys, As, Bs, Cs, you get the point
1. y + 10 - 3/2y = -y/2 + 10
2. 2r+ 7r-r - 9 = 8r - 9
3. 7 + 4p-5+p+2q = 2 + 5p + 2q (do not add different variables p and q ) together
try 4-6 on your own to get this skill down, if you need help with those just let me know
Answer:Where is the picture?
Step-by-step explanation:
