Answer:
Jada error was he multiplied the equation by (-9/4) to make the coefficient of x one. He should have multiplied it by 108
Step-by-step explanation:
Jada solved the equation
-4/9 = x/108
using the steps below:
-4/9 = x/108
(-4/9)(-9/4) = (x/108)(-9/4)
x = -1/48
Jada should have multiplied through by 108, instead of (-4/9). That was the error he made.
Multiplying through by 108 gives
(-4/9)(108) = (x/108)(108)
-48 = x
x = -48
The answer should have been
x = -48
and not
x = -1/48
Answer:
(2.5, - 10 )
Step-by-step explanation:
given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
(
,
)
here (x₁, y₁ ) = (- 16, - 12 ) and (x₂, y₂ ) = (21, - 8 ) , then
midpoint = (
,
) = (
,
) = (2.5, - 10 )
Answer:
It is given that the volume of a cone =
cubic units
Volume of cone with radius 'r' and height 'h' = 
Equating the given volumes, we get

× 

It is given that the height is 'x' units.
Therefore, 

Therefore, 
So, the expression '
' represents the radius of the cone's base in units.
Answer:
C. You take the tip amount devided by 15%. Thats 0.15. You the get the answer 97.20
Step-by-step explanation:
184 x 7 = 1288
7 x 6 = 42
so you have 42 <span>defective bulbs</span>