Answer:
The minimum number of fish each must have caught is 90 fishes
Step-by-step explanation:
The number of fishes Tisha's net can hold = 15
The number of fishes Dana's net can hold = 18
Let the total number of fishes both Tisha and Dana caught = X
15 × A = 18 × B = X
Therefore, X is the lowest common multiple (LCM) of 15 and 18 given as follows;
15 = 3 × 5
18 = 3 × 6
Therefore, the LCM of 18 and 5 = 3 × 5 × 6 = 90
Which gives, the minimum number of fish each must have caught = 90 fishes.
Since x and y must be positive, 7x and 11y are positive either. That means 7x + 11y > 0. Then we would obtain N > 0 because 7x + 11y = N. That also means N must be positive. So if we set N to be zero or negative, there would be no solution. Thus, to produce an answer of No solution, the highest number N could be is 0.
Go find ppl who need answers and get more points that’s what I’m doing sorry
Ray UW bisect VUT it means it must be breaking them in two equal parts
VUT=VUW+WUV
and mVUW= mWUV
4x+6=6x-10
-2x=-16
x=8
mWUT=6x-10=6(8)-10=38°
Your answer is 38°