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Zanzabum
3 years ago
7

The angle of depression from the top of a cliff to an ant on the ground is 35 degrees. If the ant is 280 ft from the base of the

cliff, how tall is the cliff?
Mathematics
1 answer:
Burka [1]3 years ago
5 0

Answer: 315

Step-by-step explanation: hope this is right.

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An ant can travel at a constant speed of 980 inches every 5 minutes. At this rate, how far can the ant travel in 7 minutes? *
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Reasoning:
980 divided by 5 = 196
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2 years ago
Im not sure of my answer so can anyone help me out on this
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Plz answer only if correct :)) <br> (this is trig.ratios) in
slamgirl [31]

Answer:

39

Step-by-step explanation:

Since you want to find the variable x all you have to do is simple subtraction.

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8 0
3 years ago
A bucket that weighs 5 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f
mestny [16]

Answer:

The value is W= 2640 \  ft \cdot lb

Step-by-step explanation:

From the question we are told that

The weight of the bucket is F =  5 lb

The depth of the well is x_1 =  60 \ ft

The weight of the water is W_w  =  42 lb

The rate at which the bucket with water is pulled is v  = 1.5 \  ft/s

The rate of the leak is r = 0.15 lb/s

Generally the workdone is mathematically represented as

W =  \int\limits^{x_1}_{x_o} {G(x)} \, dx]

Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

G(x) =  F  +  (W_w- Ix)

Here I is the rate of water loss in lb/ft mathematically represented as

I  = \frac{r}{v}

=> I  = \frac{0.15 }{1.5 }

=> I  = 0.1

So

G(x) =  5  +  (42- 0.1x)

=> G(x) =  47- 0.1x)

So

W =  \int\limits^{60}_{0} {47- 0.1x} \, dx]

=> W =  [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.

=> W= [47(60) - 0.05(60)^2]

=> W= 2640 \  ft \cdot lb

7 0
3 years ago
You are a male who has a high school diploma. You plan to attend college and earn a bachelor's degree. When you graduate from co
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