Question 5 Parent Function Graph

Mathematics

1 answer:

vichka [17]3 years ago

7 0

Answer:

a. Linear

A linear line is straight.

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Part 2. Show your work in solving the equation. Include the work to check your solution and show that your solution is extraneou

notsponge [240]

Extraneous solutions are the values that we get when solving equations which aren't really solutions to the equation.

<h3>What are extraneous solutions?</h3>

Your information is incomplete. Therefore, an overview will be given. An extraneous solution is the root of a transformed equation which is not a root of the original equation since it was excluded from the domain of the original equation.

The reason extraneous solutions exist is simply that some operations produce extra answers, and these operations are a part of the path to solving the problem.

Learn more about equations on:

brainly.com/question/2972832

8 0

2 years ago

I am offering another 100 points

Ivahew [28]

Answer:

$\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.$

Step-by-step explanation:

<u>Perfect squares</u>: 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, ...

To find $\sf \sqrt{75}$ , identify the perfect squares immediately <u>before</u> and <u>after</u> 75:

64 and 81

$\begin{aligned}\sf As\;\; 64 < 75 < 81\; & \implies \sf \sqrt{64} < \sqrt{75} < \sqrt{81}\\&\implies \sf \;\;\;\;\;8 < \sqrt{75} < 9 \end{aligned}$

$\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.$

See the attachment for the correct placement of $\sf \sqrt{75}$ on the number line.