Answer:
The diagram is attached.
Explanation:
Peptide just refers to two or more amino acids liking together. A dipeptide consists of two amino acids linking together. A polypeptide is more that two amino acids linking together.
Answer:
V₂ = 2.1 L
Explanation:
Given data:
Initial volume of balloon = 2.0 L
Initial temperature = 25°C
Final temperature = 35°C
Final volume of balloon in hot room = ?
Solution:
Initial temperature = 25°C (25+273= 298 K)
Final temperature = 35°C (35+273 = 308 k)
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 2.0 L × 308 K / 298 k
V₂ = 616 L.K / 298 K
V₂ = 2.1 L
Explanation:
Sankey diagrams , which are typically used to visualize energy transfers between processes, are named after the Irishman Matthew H. P. R. Sankey, who used this type of diagram in a publication on energy efficiency of a steam engine in 1898.
Sankey diagrams are ideal for visually representing energy balances.
how to use
1.Overview. The Sankey diagram displays how quantities are distributed among items between two or more stages.
2.Add a Sankey diagram. Choose the Data Visualization or Re-Visualize option from the toolbar and select Sankey Diagram.
3.Change link color and width.
4.Change node color.
5.Change labels and tooltips.
The given complex ion is as follow,
[Ru (CN) (CO)₄]⁻
Where;
[ ] = Coordination Sphere
Ru = Central Metal Atom = <span>Ruthenium
CN = Cyanide Ligand
CO = Carbonyl Ligand
The charge on Ru is calculated as follow,
Ru + (CN) + (CO)</span>₄ = -1
Where;
-1 = overall charge on sphere
0 = Charge on neutral CO
-1 = Charge on CN
So, Putting values,
Ru + (-1) + (0)₄ = -1
Ru - 1 + 0 = -1
Ru - 1 = -1
Ru = -1 + 1
Ru = 0
Result:
<span>Oxidation state of the metal species in each complex [Ru(CN)(CO)</span>₄]⁻ is zero.
Answer:
0.08 moles
Explanation:
Relative atomic mass of KMnO4 = K + Mn + O4 = 39 + 55 + 16 x 4 = 158
=> Moles in 13g of KMnO4 = 
= 
= 0.082278.. = 0.08 moles
