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algol [13]
3 years ago
10

The following equation represents the type of reaction called

Chemistry
1 answer:
Mazyrski [523]3 years ago
6 0

Answer:

Reduction

Explanation:

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

Mn⁺⁷ +3e⁻    →    Mn⁴⁺

Mn gets three electrons , its oxidation state reduced from +7 to +4 so Mn gets reduced.

Examples:

Consider the following reactions.

4KI + 2CuCl₂  →   2CuI  + I₂  + 4KCl

the oxidation state of copper is changed from +2 to +1 so copper get reduced.

CO + H₂O   →  CO₂ + H₂

the oxidation state of carbon is +2 on reactant  side and on product side it becomes  +4 so carbon get oxidized.

H₂S + 2NaOH → Na₂S + 2H₂O

The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.

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Calculate the ph of a solution whose(oh^-) is 4.583*10^-5 mole dm cube (pkw=14)​
Sergeu [11.5K]

pH of solution = 9.661

<h3>Further explanation </h3>

pH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.

pH = - log [H⁺]

So that the two quantities between pH and [H⁺] are inversely proportional because they are associated with negative values.

pOH=-log[OH⁻]

\tt pOH=-log[4.583\times 10^{-5}]\\\\pOH=5-log~4.583=4.339

pH+pOH=pKw

\tt pH=14-4.339\\\\pH=9.661

8 0
3 years ago
True or false, The universal gas constant, R, is . 0821 when we use mm Hg as our unit for pressure
ludmilkaskok [199]

Answer:

This is true.

Explanation:

R should be 0.0821

Good luck!

5 0
3 years ago
What is the pH of an aqueous solution of 1 M CH3COOH (pKa=4)
Mrac [35]

Answer:

pH = 2.

Explanation:

A weak acid is in equilibrium with its ions in a solution, so it must have an equilibrium constant (Ka). And, pKa = -logKa

Ka = 10^{-pKa}

Ka = 10⁻⁴

So, for CH₃COOH the equilibrium must be:

CH₃COOH(aq) ⇄ H⁺(aq) + CH₃COO⁻(aq)

1 M                           0                0                Initial

-x                              +x              +x               Reacted

1-x                             x                x                 Equilibrium

And the equilibrium constant:

Ka = \frac{[H+]x[CH3COO-]}{[CH3COOH]}

10^{-4} = \frac{x^2}{1-x}

Supposing x << 1:

10⁻⁴ = x²

x = √10⁻⁴

x = 10⁻² M, so the supposing is correct.

So,

pH = -log[H⁺]

pH = -log10⁻²

pH = 2

8 0
4 years ago
During which process are of rock material being moved over earth’s surface by water and wind?
shtirl [24]
Wind and water erosion
 
5 0
3 years ago
In an endothermic reaction...
kondaur [170]

Answer:

to hard im only in year 8

Explanation:

6 0
3 years ago
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