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pishuonlain [190]
3 years ago
5

If the area of square 2 is 225 units?, and

Mathematics
1 answer:
murzikaleks [220]3 years ago
3 0

Answer:

25 square units

Step-by-step explanation:

square 1 = 100 units (perimeter)

therefore each side = 25 units

square 2 = 225 square units (area)

therefore each side = 15 units

The sequence gradually decreases by 10.

Therefore square 3 each side would be 5 units.

To find the Area = 5×5

= <u>25 square units.</u>

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What is the equation of the polynomial function?
dolphi86 [110]

Answer:

f(x) = (1/2)(x-2)^2(x+1)(x+2)

Step-by-step explanation:

You can determine this by looking at the zeroes of the graph. For any zero that goes through the x-axis, the power of that zero is odd. For any zero that that "bounces" from the x-axis, the power of that zero is even.

Starting from left to right, we can see that the first zero, -2, goes through the x-axis. That means (x+2) is raised to an odd power. The second zero, -1, also goes through, so (x+1) is raised to an odd power. The last zero, 2, bounces off the x-axis, so (x-2) is raised to an even power. The only functions that satisfy this criteria are function 1 and 2.

However, we are not done yet. We need to figure out which multiplier value (1/2, 1/4) is correct. To do this, we plug in 0 for x, since we know that the y-intercept is 4. When we plug in 0, we see that f(0) = 4 for the first function. Therefore, the first function is the answer.

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7 0
4 years ago
If the area of a circle is 121pie square units, what is the diameter
velikii [3]
Since you are given the area, we can solve for radius with this equation:
A_c = \pi r^2
r = \sqrt{ \frac{A_c}{ \pi } } = \sqrt{ \frac{121 \pi }{ \pi } } = \sqrt{121} = 11

The radius is 11, so the diameter must be 2 times that, which is 22. With the correct units, the answer is 22 units²
4 0
3 years ago
I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0
4 years ago
The graph of △ABC has coordinates A(−3, −1), B(−4, −4), and C(−1, −2)
erik [133]

Answer:  

Step-by-step explanation:

3 0
2 years ago
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What does x equal in the equation 3x=x+24
erastovalidia [21]

3x = x + 24

3x - x = 24

2x = 24

x = 24 : 2

x = 12

8 0
3 years ago
Read 2 more answers
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