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AlladinOne [14]
3 years ago
11

Mixed nuts sell for $7.89 a pound. Leticia fills a bag and weighs it. The bag weighs 2.3 pounds. About how much will the bag of

nuts cost? Estimate $7.89(2.3). The bag of nuts will cost about .
Mathematics
2 answers:
Zigmanuir [339]3 years ago
7 0

Answer:

About $16

Step-by-step explanation:

To find the answer first round the weight from, 2.3 to 2. Next round the price per pound from $7.89 to 8.00. Last, multiply the weight of the bag by the price per pound. I hope this was helpful. Have a wonderful day!

RSB [31]3 years ago
6 0

Answer:

the person above me is right give them 5 stars and thanks.

Step-by-step explanation:

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There is a missing content in the question.

After the statements and before the the options given; there is an omitted content which says:

Referring to Table 16-5, in testing the coefficient of X in the regression equation (0.117) the results were a t-statistic of 9.08 and an associated p-value of 0.0000. Which of the following is the best interpretation of this result?

Answer:

C. The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05).

Step-by-step explanation:

From the given question:

The resulting regression equation can be represented as:

\hat Y = 3.37 + 0.117 X - 0.083 Q_1 + 1.28 Q_2 + 0.617Q_3

where;

the estimated number of contracts in a quarter X is the coded quarterly value with X = 0

the first quarter of 2010 Q1 is a dummy variable equal to 1 in the first quarter of a year and 0 otherwise

Q2 is a dummy variable equal to 1 in the second quarter of a year and 0 otherwise

Q3 is a dummy variable equal to 1 in the third quarter of a year and 0 otherwise

Our null and alternative hypothesis can be stated as;

Null hypothesis :

H_0 :  The quarterly growth rate in the number of contracts is not  significantly different from 0% (? = 0.05)

H_a:  The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05)

The decision rule is to reject the null hypothesis if the p-value is less than 0.05.

From the missing omitted part we added above; we can see that the   t-statistics value = 9.08 and the p-value = 0.000 .

Conclusion:

Thus; we reject the null hypothesis and accept the alternative hypothesis. i.e

The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05)

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