This snow flake-like figure can be generated by rotating an end 60° five times around the center of the hexagon. There are two forms: (i) clockwise, (ii) counterclockwise.
<h3>What is the angle of rotation of a snow flake?</h3>
Geometrically speaking, snow flakes represent <em>regular</em> hexagons. <em>Regular</em> hexagons can divided into six concentric <em>regular</em> triangles, whose <em>central</em> angles have a measure of 60°. This <em>fractal</em> figure can be generated by rotating 60° five times around the center.
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Given that the angles of the two sectors are equal, we can find the relationship between the angles, radii, and the lengths of the arc
The length of the arc (S) is given by the formula
Then we can make the angle the subject of the formula
For the first sector
For the second sector
Simplifying the equation, we will obtain
<span>80.925 is the correct answer</span>
Answer: sure it's c
Step-by-step explanation: