31.3m/s
Explanation:
Given parameters:
Mass of rock = 40kg
Height of cliff = 50m
Unknown:
Speed of rock when it hits ground = ?
Solution:
We are going to use the appropriate motion equation to solve this problem
The rock is falling with the aid of gravitational force. The force is causing it to accelerate with an amount of velocity.
Using;
V² = U² + 2gH
V = unknown velocity
U = initial velocity = O
g = acceleration due to gravity = 9.8m/s²
H = height of fall
since the initial velocity of the bodyg is 0
V² = 2gH
V= √2gH = √2 x 9.8 x 50 = 31.3m/s
learn more:
Velocity brainly.com/question/4460262
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Answer:
197.76 m
Explanation:
r = Radius of the path = 20.6 km = 
= The angle subtended by moon = 
Distance traveled is given by
The distance traveled by the jet is 197.76 m
I think Im gonna have to go with C 6.00 T/s but Im not sure
