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My name is Ann [436]
3 years ago
5

If you increase the size of the resistor and keep the voltage the same, what will happen to the current

Physics
1 answer:
Grace [21]3 years ago
8 0

Answer:

If voltage is kept constant across the resistor itself, it' current will reduce. If the resistance is part of oscillator circuit, frequency response will change. If it is in series with capacitor or inductor, it will change the damping effect.

Explanation:

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If the accuracy in measuring the position of a particle increases, the accuracy in measuring its velocity will
astraxan [27]

Answer:

Therefore the answer is the precision in the speed DECREASES

Explanation:

In quantum mechanics, we have the uncertainty principle that establishes that when the accuracy of the position increases the accuracy  the speed decreases, being related by the expression

               Δx Δv ≥  h'/ 2

                h' = h/2π

Therefore the answer is the precision in the speed DECREASES

7 0
3 years ago
How i can change my bad habits and one is i always trust peopñe
Lelu [443]

what? I guess:

  • practice different habits. If you fail don't give up.
  • don't always trust people, some are not what they seem.

this question doesn't make any sense...

5 0
3 years ago
Read 2 more answers
Assapp!!!’!!!!!!!! !!!!!!
dlinn [17]

Answer:

delta r(x) = (delta (r)) * cos(alpha), delta r(y) = (delta(r)) * sin(alpha)

Explanation:

Well it's a simple rule I guess...

6 0
3 years ago
A block whose weight is 45.8 N rests on a horizontal table. A horizontal force of 36.6 N is applied to the block. The coefficien
Liula [17]

Answer:

Yes it will move and a= 4.19m/s^2

Explanation:

In order for the box to move it needs to overcome the maximum static friction force

Max Static Friction = μFn(normal force)

plug in givens

Max Static friction = 31.9226

Since 36.6>31.9226, the box will move

Mass= Wieght/g which is 45.8/9.8= 4.67kg

Fnet = Fapp-Fk

= 36.6-16.9918

=19.6082

=ma

Solve for a=4.19m/s^2

7 0
3 years ago
Two loudspeakers are placed side by side and driven by the same source at 500 Hz. A listener is positioned in front of the two s
Oliga [24]

Answer:

0.68 m

Explanation:

We know that the speed of sound in air is a product of frequency and wavelength. Taking speed of sound in air as 340 m/s

V=frequency*wavelength

Then wavelength is given by 350/500=0.68 m

Therefore, to repeat constructive interference at the listener's ear, a distance of 0.68 m is needed

4 0
3 years ago
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