Answer:
The approximate probability that 10 squared centimeters of dust contains more than 10110 particles is 0.1357
Step-by-step explanation:
For a sample of 10 sqaured centimeters of dust, the total amount of asbestos particles has a Poisson distribution with a mean of 1000/1 * 10 = 10000.
We will approximate this probability to a normal distribution. The variance is also 10000 (because it is poisson), therefore the standard deviation is √10000 = 100. Lets call X the distribution, and W its standarization, given by
We have
Where is the cummulative distribution function of a standard normal distribution. The values of are well known and they can be found in the attached file.
We conclude that the approximate probability that 10 squared centimeters of dust contains more than 10110 particles is 0.1357.
Answer:
a) <em>Mean number of beans = 33.4 per coco pad</em>
<em>b) Standard deviation of the beans = 5.2 per coco pad</em>
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
a)
Given data 30, 28, 30, 35, 40, 25, 32, 36, 38 and 40.
mean of beans
x⁻ = ∑x/n
<em>Mean number of beans per coco pad = 33.4</em>
<em>step(ii):-</em>
<em>b) </em>
<u><em>standard deviation</em></u>
<em>∑(xi - x⁻)² = (30-33.4)²+ (28-33.4)²+(30-33.4)²+(35-33.4)²+(40-33.4)²+(25-33.4)²+(32-33.4)²+(36-33.4)²+ (38-33.4)²+(40-33.4)²</em>
<em>On calculation , we get</em>
<em> ∑(xi - x⁻)² = 242.4</em>
<em>standard deviation </em>
<em> = </em><em></em>
<em>Standard deviation of the beans (σ) = 5.2 per coco pad</em>
Given a vetex (h,k) of a function parabola, the corresponding equation is:
With (h,k)=(2,5) we get the equation:
In order to find a, we use the given point (3,7) like this:
The equation is then: