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vova2212 [387]
4 years ago
9

________ are high latitude soils containing permafrost and large amounts of organic matter.

Biology
1 answer:
viva [34]4 years ago
4 0
Gelisols are high latitude soils containing permafrost and large amounts of organic matter. ]
Gelisols are soils that are permanently frozen or contain evidence of permafrost near the soil surface. They are found in the Arctic and Antarctic, as well as at extremely high elevations. Additionally they are also found at extremely high elevations in the lower latitudes. 
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A particular enzyme will usually interact with... *
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It’s corresponding molecule that or bonds to. I think it is a substrate.
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3 years ago
Whats the general relationship between mass and gravitational force
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The gravitational force on an object increases as the object’s mass increases.

Explanation:

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The damp soil within a forest in which a mushroom grows is a...? Habitat ? Ecosystem? Community? Population?
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Community, habitat is in general and ecosystem is the whole place, not just the soil.
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Read 2 more answers
Which type(s) of cell division (mitosis, meiosis l, meiosis Il) reduce(s) the chromosome number by half? Which type(s) of cell d
PSYCHO15rus [73]

Answer:

Which type(s) of cell division reduce(s) the chromosome number by half?

                           Meiosis l

Which type(s) of cell division can be classified as reductional?  

                            Meiosis I

Which type(s) of cell division can be classified as equational?

                           Mitosis and Meiosis II

Explanation:

Meiosis is a type of cell division which occurs in the germ or reproductive cells to produce gametes. It is completed in the two stages, meiosis I and meiosis II.  The cells which are going to divide by meiosis are diploid having two sets of chromosomes. Meiosis I is the first stage of the meiosis. At the end of meiosis I two daughter cells are formed having only 1 set of chromosomes and chromosome numbers are reduced to half. Thus, meiosis I is a reductional division.  

Mitosis and meiosis II is the equational division as after division chromosome number remains the same as in the parent.  

6 0
4 years ago
Suppose that an adult black bear adds 50 pounds of fat in order to survive while hibernating through the winter. how much glycog
NemiM [27]

Answer: The correct answer would be 112.5 pounds

Explanation:

Let us first covert the pound into grams. We know that 1 pound is equal to 453.59 grams.

Thus, 50 pound of fat = 50 x 453.59 = 22,679.5 grams.

We know that, 1 gram of fat releases 9 Kcal of energy. Thus, total energy produced by 22679.5 grams = 9 x 22679.5 = 204,115.5 Kcal

Glycogen is carbohydrate thus, it will produce 4 Kcal of energy per gram.

Thus, 4 x C = 204,115.5 (where C is the grams of glycogen)

⇒ C = \frac{204115.5}{4}

⇒ C = 51,028.875 grams

Using 1 pound = 453.59 grams, we con convert 51,028.875 grams into pounds:

453.59 = 1

1 = \frac{1}{453.59}

51,028.875 = \frac{1}{453.59} x 51028.875

= 112.5 pounds

Thus, 112.5 pound of glycogen would be needed to produce the same amount of energy as produced by 50 pounds of fat.

8 0
3 years ago
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