Answer: B. The anion affects the color of the solution more than the intensity of the color.
Explanation:
An ionic bond is gotten when an electron is transferred from a metal atom to a non-metal one. It should be noted that the ionic bonds simply has an anion and a cation.
An anion is formed when a valence election is gained by a non metal while a cation is formed when the metal ion misplaces a valence electron.
The effect of the anion of an ionic compound on the appearance of the solution is that the anion affects the color of the solution more than the intensity of the color.
Answer:
C. Y & Z
Explanation:
V, W are imaginary metals here because their valence electrons are typically less than 4. X, Y, Z are non-metals and have higher valence electrons. Here, if V or W bind with X, Y, or Z we make ionic bond (because metal + non metal = ionic). But, if X binds with Y or Z or any combinations of any two of the three non-metals results in covalent bond (non metal + non metal = covalent).
Thus, Y and Z make covalent.
Carbon dioxide is a carbon atom and two oxygen atoms, therefore CO2
For the others, they are hydrocarbons.
The first part of the name is determined by how many carbon atoms there are. The second part, is by the type. Alcohol, Alkane, Alkene, alkynes, acid, esters, amides.
Answer:
I think its b
Explanation:
but I wouldn't depend on this answer
To determine what gas is this, we use Graham's Law of Effusion where it relates the rates of effusion of gases and their molar masses. We do as follows:
r1/r2 = √(M2 / M1)
Let 1 be the the unkown gas and 2 the H2 gas.
r1/r2 = 0.225
M2 = 2.02 g/mol
0.225 = √(2.02 / M1)
M1 = 39.90 g/mol
From the periodic table of elements, most likely, the gas is argon.
