A hiker climbs to the top of a mountain at rate of 0.5 m/hr. The speed of hiker is 1.3 x 10⁻⁴ m/s and the velocity of the hiker is 1.3 x 10⁻⁴ m/s west.
Speed is a scalar quantity. It is used to measure the distance traveled in a period of time. It is represented by -
s = d/Δt
where,
s = speed
d = distance
Δt = change in time
Velocity is a vector quantity. It is used to measure the change in position, that is, displacement over the change in time. It is represented by -
v = Δs / Δt
where,
v = velocity
Δs = change in position/displacement
Δt = change in time
The standard unit of velocity and speed both is m/s.
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I believe the answer is B. Definitely not D or A, and C doesn't makes sense.
Answer:
133.56kPa
Explanation:
Applying Pressure Law,
P/T = P'/T'....................... Equation 1
Where P = Initial pressure, T = Initial Temperature, P' = Final pressure, T' = Final Temperature.
From the question, we were asked to calculate P'
There, we make P' the subject of the equation
P' = PT'/T...................... Equation 2
Given: P = 100kPa, T = 25°C = (273+25) = 298K, T' = 125°C = (273+1250K = 398 K
Substitute these values into equation 2
P' = (100×398)/298
P' = 133.56kPa
Hence the pressure is 133.56kPa