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3 years ago

How would you be able to use the spectrum of each gas to establish its identity

Chemistry

1 answer:

NNADVOKAT [17]3 years ago

3 0

You could compar and contrast the identities so you can compare them and identify them

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Does anyone know how to do this?

rjkz [21]

Answer:

I know

Explanation:

Sike i dont know. Sorry man, but i dont know what that means - are you on crack? do you need therapy because I am a great therapist. Hmu if you'd like.

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3 years ago

A. Element X has a

vlabodo [156]

The mass is written as a superscript and the charge is written as a subscript in the isotope notation of element X as follows $\frac{292}{119} X$ .

The isotope notation may also be called the nuclear notation of an element. It helps us to identify what element is represented. It usually comprises of the atomic mass of the element written as a superscript and then the atomic number or charge written as a subscript.

In this case, we have an element with an mass of 292 amu and charge of 119. In this case, the isotope notation of element X is $\frac{292}{119} X$ .

Learn more: brainly.com/question/5838915

8 0

2 years ago

Can oxygen ever have more then 8 protons? why or why not

EastWind [94]

No because it changes its composition to ozone

3 0

3 years ago

1. When two atoms with different electronegativities are bonded together, a bond dipole exists. These are displayed with an arro

Natali5045456 [20]

Answer:

In order: LOWER, HIGHER, NEGATIVE, POSITIVE, INCREASE

Explanation:

First you must consider the definition of electronegativity.

All in all, electronegativity is the ability of an atom to attract electrons to itself. For this explanation, let's just consider the groups 1, 2, 13-17, and the noble gases of the periodic table. Furthermore, let's also consider the octet rule. The octet rule says that the last orbit of an atom tends to have 8 electrons in order to be stable.

If you take an atom like Sodium (Na) and search its distribution of electrons by levels, you'll see these number in the last two orbits: 8.1

The penultimate orbit has 8 electrons and the last one has only 1. Therefore, in order to futfill the octet rule what do you think it's easier? Losing the last electron and leaving the 8 electrones of the penultimate orbit as last orbit? Or maybe taking 7 electrons for the last orbit and, hence, futfilling the octet? Well, the answer is the first case.

The more you move from group to group (i.e, rightwards in the periodic table), more electrons will have in their last orbit.

So, in order to respond your question: Yes you should display it like this:

A --> B

Consider A and B two random atoms, for which B's electronegativity is higher than A's. This arrow shows the tendency of the electron flow.

As electrons go to the more electronegative atom, the whole electronic ''cloud'' will tend to be closer to B, because this atom is more electronegative. Hence, there will be a partial (not fixed) negative charge on B rather than on A. This is due to B's high electronegativity. This means that the negative charge will spend more time on B rather than on A, this is what partial negative charge means.

The higher the electronegativity is, the higher the magnitudes of the partial charges --> Therefore, these partial charges are increased and sometimes it might lead to the chemical bond breakage.

8 0

3 years ago

Which radioisotopes have the same decay mode and have half-lives greater than

AveGali [126]

The correct answer is (3)

I-131 and P-32

The explanation:

according to attached table:

- we can see that the half life of p 32 is 14.28d (more than one hour)

- and the half life of I-131 is 8.021 d (more than one hour)

and They both have β- decay mode and with half-lives greater than hour.