Answer:
At 0.58 L of 0.540 M NaOH solution contain 12.5 g NaOH.
Explanation:
Given data:
At volume = ?
Mass of NaOH = 12.5 g
Molarity of solution = 0.540 M
Solution:
First of all we will calculate the number of moles of sodium hydroxide.
Number of moles = mass/molar mass
Number of moles = 12.5 g / 40 g/mol
Number of moles = 0.3125 mol
Volume of NaOH:
Molarity = number of moles / volume in L
Now we will put the values.
0.540 M = 0.3125 mol / volume in L
volume in L = 0.3125 mol / 0.540 mol/L
volume in L = 0.58 L
Answer:
This reaction is sometimes referred to as the Baeyer test. Because potassium permanganate, which is purple, is reduced to manganese dioxide, which is a brown precipitate, any water‐soluble compound that produces this color change when added to cold potassium permanganate must possess double or triple bonds.
Explanation:
<h2><em>I</em><em> </em><em>HOPE</em><em> </em><em>IT'S</em><em> </em><em>HELP</em><em> </em></h2>
They are called isotopes.
H₂SO₄ + 2NaOH = Na₂SO₄ + 2H₂O
v(NaOH)=46 ml=0.046 l
c(NaOH)=1.0 mol/l
v(H₂SO₄)=55 ml=0.055 l
n(NaOH)=v(NaOH)*c(NaOH)
n(H₂SO₄)=0.5n(NaOH)
c(H₂SO₄)=n(H₂SO₄)/v(H₂SO₄)=0.5*v(NaOH)*c(NaOH)/v(H₂SO₄)
c(H₂SO₄)=0.5*0.046*1.0/0.055=0.418 mol/l
The concentration of the H₂SO₄ is 0.418M.
