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insens350 [35]
3 years ago
5

You have a sample containing 2.39 moles of silver. How many atoms of silver are in this sample?

Chemistry
1 answer:
soldi70 [24.7K]3 years ago
4 0

Answer:

14.3878 x 10^23 molecules Ag

Explanation:

2.39 mol Ag     6.02 x 10^23

----------------- x   ------------------ =  14.3878 x 10^23 Molecules Ag

     1                        1 mol

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Mamont248 [21]

Answer:  Ions result from atoms or molecules that have gained or lost one or more valence electrons, giving them a positive or negative charge. Those with a negative charge are called anions and those with a positive charge are called cations. Cations (positively-charged ions) and anions (negatively-charged ions) are formed when a metal loses electrons, and a nonmetal gains those electrons. ... And all of them form an anion with a single negative charge. The VIA elements gain two electrons to form anions with a 2- charge.

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Which of the fallowing elements is the most reactive?
Alexxx [7]
Which elements are most reactive?

The alkali metals, found in group 1 of the periodic table (formerly known as group IA), are very reactive metals that do not occur freely in nature. These metals have only one electron in their outer shell. Therefore, they are ready to lose that one electron in ionic bonding with other elements.

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5 0
4 years ago
What type of chemical reaction occurs when more energy Is released during the chemical reaction than is needed to start the chem
Ksju [112]

Answer:

Explanation:

Exothermic Reactions

Exothermic Reactions

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3 0
3 years ago
Calculate the empirical formula of a compound that is 42.9% Carbon and 57.1% Oxygen.
Marrrta [24]

Answer:

CO.

Explanation:

Assuming the given percentages are by mass, we can solve this problem via imagining we have <em>100 g of the compound</em>, if that were the case we would have:

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  • 57.1 g of O

Now we <u>convert those masses into moles</u>, using the<em> elements' respective molar masses</em>:

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As the number of C moles and O moles is roughly the same, the empirical formula for the compound is <em>CO</em>.

4 0
3 years ago
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