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DENIUS [597]
3 years ago
9

X+1½= 3 ⅓What is x?​

Mathematics
1 answer:
sdas [7]3 years ago
3 0

Answer:

1 5/6

Step-by-step explanation:

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What is 1.52 as a fraction?
miss Akunina [59]
The number 1.52 can be expressed using this fraction 152/100. This fraction is equal to 38/25 when reduced to lowest terms. This fraction is also equal to 1 13/25 when expressed as a mixed number.
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Question 8
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Answer:

Exponential function

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How many degrees are in the angle formed by the hands of the clock?
QveST [7]

Answer:

90°

Step-by-step explanation:

15 mins = 1/4 of full circle

1/4 of 360 = 90

90°

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6 0
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Read 2 more answers
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 7.1 parts
satela [25.4K]

Answer:

t=\frac{6.6-7.1}{\frac{1.0}{\sqrt{26}}}=-2.550    

Step-by-step explanation:

Data given and notation  

\bar X=6.6 represent the sample mean

s=1.0 represent the sample standard deviation

n=26 sample size  

\mu_o =7.1 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is different from 7.1 ppm, the system of hypothesis would be:  

Null hypothesis:\mu = 7.1  

Alternative hypothesis:\mu \neq 7.1  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{6.6-7.1}{\frac{1.0}{\sqrt{26}}}=-2.550    

5 0
3 years ago
Mr. &amp; Mrs. Thompson drove 300 miles in October. They drove 2 times as many miles in December as they did in October. They dr
Marina86 [1]

Answer:1200 miles

Step-by-step explanation:

Given

Mr. and Mrs. Thompson drove 300\ miles in October

They drove 2  times as many miles in December

so they drove 2\times 300=600\ miles in December

In November they drove 2 times as many as in december

=2\times 600=1200\ miles  

So they drive 1200 miles in November

7 0
4 years ago
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