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Ostrovityanka [42]
3 years ago
3

Venn diagrams are used for comparing and contrasting different topics. The overlapping sections show characteristics that the to

pics have in common, and the sections that are unique to each topic show the characteristics apply to only that topic.
Overlapping circles are labeled solid on top, liquid at right, gas at left, with the intersection of all three labeled state of matter.
Which Venn diagram accurately describes what characteristics of solids, liquids, and gasses could be added to this diagram?

Overlapping circles are labeled definite shape most dense at top, mid-level density at right, definite volume least dense at left, with the intersection labeled state of matter.
Overlapping circles are labeled definite shape most dense at top, mid-level density at right, least dense at left, with the intersection of all three labeled state of matter. The intersection of the top and right circles is labeled definite volume.
Overlapping circles are labeled definite shape most dense at top, definite volume mid-level density at right, least dense at left, with the intersection of all three labeled state of matter. The intersection of the left and right circles is labeled definite shape.
Overlapping circles are labeled definite shape least dense at top, definite mid-level density at right, most dense at left, with the intersection of all three labeled state of matter. The intersection of the left and right circles is labeled definite shape.
Physics
2 answers:
Anarel [89]3 years ago
6 0

Answer:

dat too much to read tooooooo much

Explanation:

Evgesh-ka [11]3 years ago
3 0
Ok so.... I’m kinda confused but I’ll try to help
Don’t we need an image cuz it says which diagrams but ur expanding to me so nvm
Is it answer choice??
I’m sorry break it down please
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Which nucleus complete the following equation
rosijanka [135]

(C) ^{208}_{84}\text{Po}

Explanation:

^{212}_{86}\text{Rn} \rightarrow \:^4_2\text{He} + \:^{208}_{84}\text{Po}

7 0
3 years ago
A ball is thrown directly upward from a height of 3 ft with an initial velocity of 28 ​ft/sec. the function ​s(t)equalsminus16ts
borishaifa [10]

Answer:

t = 0.875 s

s_{max} = 15.25 ft

Explanation:

Position of the ball as a function of time is given as

s(t) = s_o + v_y t + \frac{1}{2}at^2

s(t) = 3 + 28 t - 16 t^2

now we know that when ball will attain maximum height then the differentiation of the position with respect to time will become zero

so we have

\frac{ds}{dt} = 0

0 = 0 + 28 - 32 t

t = 0.875 s

now the maximum height is given as

s_{max} = 3 + 28(0.875) - 16(0.875)^2

s_{max} = 15.25 ft

4 0
4 years ago
What occurs when the pitch increases and the sound source is in motion? explain your answer.
Hoochie [10]
If you're listening to a sound that has a steady pitch, and suddenly the
pitch goes up, then you know that two things could have happened:

EITHER ...

-- The person or other source making the sound could have
raised the pitch of the sound being produced.

OR ...

-- The person or other source making the sound could have
started moving toward you.

OR ...

-- both.

Even if the pitch of the sound leaving the source doesn't change,
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3 0
3 years ago
Frente a una lente convergente delgada se coloca un objeto a una distancia de 50 cm. La imagen de este objeto aparece del otro l
katovenus [111]

Answer:

La distancia focal del objetivo es de aproximadamente 30,77 cm

Explanation:

Los parámetros dados son;

La distancia del objeto desde la lente, u = 50 cm

La distancia de la imagen desde la lente, v = 80 cm

La fórmula del espejo se puede escribir de la siguiente manera;

\dfrac{1}{f} = \dfrac{1}{v} + \dfrac{1}{u}

Dónde;

f = La distancia focal de la lente

v = La distancia de la imagen desde la lente

u = La distancia del objeto desde la lente

Sustituyendo los valores da;

\dfrac{1}{f} = \dfrac{1}{80} + \dfrac{1}{50} = \dfrac{80 + 50}{4000} = \dfrac{13}{400}

\therefore  f = \dfrac{400}{13}  = 30\dfrac{10}{13} \ cm

La distancia focal de la lente, f = 30¹⁰/₁₃ cm ≈ 30,77 cm.

La distancia focal del objetivo ≈ 30,77 cm.

4 0
3 years ago
What are the tool needed to find the density of an irregularly shaped object?
lesya [120]
To find density of an irregular object, you need to find the mass and volume.

The tool you need is a triple beam balance, a graduated cylinder, and paper, pencil, etc
5 0
3 years ago
Read 2 more answers
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