Frente a una lente convergente delgada se coloca un objeto a una distancia de 50 cm. La imagen de este objeto aparece del otro l
1 answer:
Answer:
La distancia focal del objetivo es de aproximadamente 30,77 cm
Explanation:
Los parámetros dados son;
La distancia del objeto desde la lente, u = 50 cm
La distancia de la imagen desde la lente, v = 80 cm
La fórmula del espejo se puede escribir de la siguiente manera;
Dónde;
f = La distancia focal de la lente
v = La distancia de la imagen desde la lente
u = La distancia del objeto desde la lente
Sustituyendo los valores da;
La distancia focal de la lente, f = 30¹⁰/₁₃ cm ≈ 30,77 cm.
La distancia focal del objetivo ≈ 30,77 cm.
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(BELOW YOU CAN FIND ATTACHED THE IMAGE OF THE SITUATION)
Answer:
Explanation:
For this we're going to use conservation of mechanical energy because there are nor dissipative forces as friction. So, the change on mechanical energy (E) should be zero, that means:
(1)
With the initial kinetic energy,
the initial potential energy,
the final kinetic energy and
the final potential energy. Note that initialy the masses are at rest so
, when they are released the block 2 moves downward because m2>m1 and finally when the mass 2 reaches its maximum displacement the blocks will be instantly at rest so
. So, equation (1) becomes:
(2)
At initial moment all the potential energy is gravitational because the spring is not stretched so and at final moment we have potential gravitational energy and potential elastic energy so
, using this on (2)
(3)
Additional if we define the cero of potential gravitational energy as sketched on the figure below (See image attached), and we have by (3) :
(4)
Now when the block 1 moves a distance d upward the block 2 moves downward a distance d too (to maintain a constant length of the rope) and the spring stretches a distance d, so (4) is:
dividing both sides by d
, with k the constant of the spring and g the gravitational acceleration.
