Answer:
A sled and its rider are moving at a speed of along a horizontal stretch of snow, as Figure 4.24a illustrates. The snow exerts a kinetic frictional force on the runners of the sled, so the sled slows down and eventually comes to a stop. The coefficient of kinetic friction is 0.050. What is the displacement x of the sled?
<span>The lighter object is in orbit around the heaviest, and the Sun is the heaviest object in the Solar System</span>
Answer:
100 V
Explanation:
Hi there!
Ohm's law states that
where V is the voltage, I is the current and R is the resistance.
Plug the given information into Ohm's law (R=50, I=A)
![V=IR\\V=(2)(50)\\V=100](https://tex.z-dn.net/?f=V%3DIR%5C%5CV%3D%282%29%2850%29%5C%5CV%3D100)
Therefore, the voltage across this current is 100 V.
I hope this helps!
Answer:
<em>The range is 35.35 m</em>
Explanation:
<u>Projectile Motion</u>
It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.
Being vo the initial speed of the object, θ the initial launch angle, and
the acceleration of gravity, then the maximum horizontal distance traveled by the object (also called Range) is:
![\displaystyle d={\frac {v_o^{2}\sin(2\theta )}{g}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%3D%7B%5Cfrac%20%20%7Bv_o%5E%7B2%7D%5Csin%282%5Ctheta%20%29%7D%7Bg%7D%7D)
The projectile was launched at an angle of θ=30° with an initial speed vo=20 m/s. Calculating the range:
![\displaystyle d={\frac {20^{2}\sin(2\cdot 30^\circ )}{9.8}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%3D%7B%5Cfrac%20%20%7B20%5E%7B2%7D%5Csin%282%5Ccdot%2030%5E%5Ccirc%20%29%7D%7B9.8%7D%7D)
![\displaystyle d={\frac {400\sin(60^\circ )}{9.8}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%3D%7B%5Cfrac%20%20%7B400%5Csin%2860%5E%5Ccirc%20%29%7D%7B9.8%7D%7D)
![d=35.35\ m](https://tex.z-dn.net/?f=d%3D35.35%5C%20m)
The range is 35.35 m