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3 years ago

What occurs when the pitch increases and the sound source is in motion? explain your answer.

1 answer:

3 0

If you're listening to a sound that has a steady pitch, and suddenly the
pitch goes up, then you know that two things could have happened:

EITHER ...

-- The person or other source making the sound could have
raised the pitch of the sound being produced.

OR ...

-- The person or other source making the sound could have
started moving toward you.

OR ...

-- both.

Even if the pitch of the sound leaving the source doesn't change,
you would still hear it increase if the source starts moving toward
you. That's the so-called "Doppler effect".

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Increasing the mass attached to a spring will decrease the angular frequency of its vibrations. True or False

Scrat [10]

Answer:

decreases

Explanation:

The angular frequency of the mass is given by

$\omega =\sqrt{\frac{k}{m}}$

where, k is the spring constant and m be the mass of the body which is doing oscillations.

if the mass of the body increases, so the value of angular frequency decreases, as the angular frequency is inversely proportional to the square root of the mass of the body.

4 0

4 years ago

Which layer of earth is a solid rock?

Sholpan [36]

Answer:

Crust

Explanation:

5 0

3 years ago

Calculate the average Power in kilowatts required to pull a car up a ramp in the amount of work is 250 KJ over a period of 45 se

kherson [118]

For this case we have that by definition, the average power is given by:

$P = \frac {W} {t}$

Where:

W: It is the work done

t: It's time

According to the data we have to:

$W = 250 \ KJ = 250,000 \ J\\t = 45 \ s$

So:

$P = \frac {250,000} {45}\\P = 5555.55 \ watts = 5.56 \ kw$

Answer:

$5.56 \ kw$

5 0

4 years ago

Two 2 kg masses is placed at either end of a rod that has a mass of .5 kg and a length of 3 m. What is the moment of inertia if

sergij07 [2.7K]

Explanation:

a) $I=\displaystyle \sum_{i}m_ir_i^2$

where $r_i$ is the distance of the mass $m_i$ from the axis of rotation. When the axis of rotation is placed at the end of the rod, the moment of inertia is due only to one mass. Therefore,

$I= mr^2 = (2\:kg)(3\:m)^2 = 18\:kg-m^2$

b) When the axis of rotation is placed on the center of the rod, the moment is due to both masses and the radius r is 1.5 m. Therefore,

$\displaystyle I= \sum_{i}m_ir_i^2 = 2(2\:kg)(1.5\:m)^2 = 9\:kg-m^2$

7 0

3 years ago

Ok plz answer and tell me how to do it

kirza4 [7]

Answer: 25N

method: total force in the right hand direction is 100N and total force in the left hand direction is 125N. To get the net force, we add forces if they are in the same direction and substract if they are in opposite directions. since 100N and 125N are in opposite directions, we substract the larger value from the smaller value. Then we get 25N in the left hand direction as the final answer.

4 0

4 years ago