3 years ago

How do you find the length of the diagonals?

Mathematics

1 answer:

dlinn [17]3 years ago

8 0

Answer:

6 ft, and 6√3

Step-by-step explanation:

We have rhombus, so all sides are equal . Rhombus are divided into 4 congruent triangles.

The triangle is special. 30-60,90. Hypotenuse is 6ft.

long leg=hypotenuse*sin 60°=6*√3/2=3√3.

Long diagonal of rhombus is 2*3√3=6√3 ft.

Short leg = hypotenuse *cos(60)°=6*(1/2)=3

short diagonal=2*3=6ft

You might be interested in

Help! Will Give that crown

wolverine [178]

Answer:

3500-26= 3474

3929-37=3892

any more help just ask :)

4 0

3 years ago

A store pays $20 for a set of headphones. The store sells the set of headphones for $70. Your classmate says that the markup is

Natalija [7]

Yes. your classmate is correct

4 0

2 years ago

Read 2 more answers

What is 90.95 rounded to the nearest whole number

Kamila [148]

90.95 rounded to the nearest whole # is 91

8 0

3 years ago

Read 2 more answers

What is the slope of the line that passes through the points (8,4) and (20,-4)?

irga5000 [103]

Answer:

for (8,4) is 2 and for (20,_4) is _5

6 0

3 years ago

Find the value of x

iVinArrow [24]

Answer:

x = 121

Step-by-step explanation:

Let the measure of the altitude of the given triangle be h units.

By geometric mean theorem:

$h = \sqrt{23 \times x} \\ \\ h = \sqrt{23x} \\ \\ now \: by \: pythagors \: theorem \\ \\ {(x + 11)}^{2} = {h}^{2} + {x}^{2} \\ \\ \cancel{{x}^{2}} + 22x + 121 = {( \sqrt{23x} )}^{2} + \cancel{{x}^{2}} \\ \\ 22x + 121 = 23x \\ \\ 22x - 23x = - 121 \\ \\ - x = - 121 \\ \\ x = 121$

4 0

3 years ago