After putting the value of y from the second equation to the first equation, the resultant equation is
.
GIven:
The equations are:

It is required to put the value of y from second equation to the first equation.
<h3>How to solve equations?</h3>
The value of y from the second equation is,

Now, put this value of y in the first equation as,

Therefore, after putting the value of y from the second equation to the first equation, the resultant equation is
.
For more details about equations, refer to the link:
brainly.com/question/2263981
Answer:
1. 208 in^2
Step-by-step explanation:
1. We can break the shape up into a rectangle in the middle and 2 triangles on either side of said rectangle.
The dimensions of the rectangle are 8 in by 20 in, and we only know one leg of the triangle as well as the hypotenuse.
If we know one leg and the hypotenuse we can use the pythagorean theormed to sovle for the other side and get 6 in.
So we have
(8 * 20) + 2((1/2)(6)(8))
160 + 48
208 in^2
Just put 3.150 lol that what I did