Can someone helppppp ?

brianna bought a computer game for $36 with a coupon for %25 off, How much would it cost without the coupon

Butoxors [25]

The game would cost $45

7 0

2 years ago

Please help I’m really confused. I will give BRAINLIEST!

stiv31 [10]

Answer:

t = 115

s = 60

g(x) = 10/23x - 10

Step-by-step explanation:

find s first since its easy (it goes up by 10's)

then take a pair from the table that corresponds such as 69 for x and 30 for g(x) and turn them into a fraction:

69/30

do the same for t:

t/50

equal 69/30 to t/50 and solve using cross multiplication:

69/30 = t/50 =

30t = 3450

/30 /30

t = 115

honestly had a little hard time finding the equation but basically I simplified the fraction 30/69 to get 10/23 for slope and then I insert a corresponding x and y value into y= mx+b with the slope value to find b.

5 0

2 years ago

Find the product of x^2(4x-3)

TEA [102]

Answer:

4 x^3 - 3 x^2

Step-by-step explanation:

Expand the following:

x^2 (4 x - 3)

x^2 (4 x - 3) = x^2×4 x + x^2 (-3):

4 x^2 x - 3 x^2

x^2×4 x = x^(2 + 1)×4:

4 x^(2 + 1) - 3 x^2

2 + 1 = 3:

Answer: 4 x^3 - 3 x^2

8 0

2 years ago

Read 2 more answers

Here are the first four terms of an arithmetic sequence. 3 10 17 24 Find, in terms of n, an expression for the nth term of this

ollegr [7]

Answer:

$a_{n}$ = 7n - 4

Step-by-step explanation:

The n th term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 3 and d = a₂ - a₁ = 10 - 3 = 7 , thus

$a_{n}$ = 3 + 7(n - 1) = 3 + 7n - 7 = 7n - 4

8 0

2 years ago

Pls show full working out

sweet-ann [11.9K]

Answer:

Question 1a. i) $x=1.8m$

Question 1a. ii) $Volume=27.6m^3$

Question 1b) $Volume=65.9m^3$

Explanation:

Question 1 a. i) Find the value of x.

$tan(\theta )=\dfrac{opposite\text{ }leg}{adjacent\text{ }leg}$

For the smalll triangle you can write:

$tan(\theta )=\dfrac{x}{1m}$

For tthe big triangle:

$tan(\theta )=\dfrac{x+2.7m}{2.5m}$

Substitute:

$\dfrac{x}{1m}=\dfrac{x+2.7m}{2.5m}$

Solve for x:

$2.5x=x+2.7m\\\\2.5x-x=2.7m\\\\1.5x=2.7m\\\\x=2.7m/1.5\\\\x=1.8m$

Question 1a ii) Find the volume of the frustrum

Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m

Formula:

$Volume=(1/3)\pi \times radius^2\times height$

Substitute:

$Volume=(1/3)\pi \times (2.5m)^2\times 4.5m=9.375\pi m^3$

Find the volume of a cone with heigth = 1.8m and radius = 1m

$Volume=(1/3)\pi \times (1m)^2\times 1.8m=0.6\pi m^3$

Subtract the volume of the small cone from the volume of the big cone

$Volume\text{ }of\text{ }frustrum=9.375\pi m^3-0.6\pi m^3=8.775\pi m^3\approx 27.6m^3$

Question 1b. Calculate the volume of the bin

i) Upper frustrum

This is the same frustrum from the equation of above, thus ist volume is 27.6m³.

ii) Lower frustrum

$\dfrac{x}{2.0m}=\dfrac{x+2.4m}{2.5m}$

$2.5x=2(x+2.4m)\\\\2.5x=2x+4.8m\\\\0.5x=4.8m\\\\x=9.6m$

$Volume=(1/3)\pi \times (2.5m)^2\times (9.6m+2.4m)-(2.0m)^2\times (9.6m)$

$Volume=38.3m^3$

iii) Add the volume of the two frustrums

$Volume=27.6m^3+38.3m^3=65.9m^3$

6 0

2 years ago